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zloy xaker [14]
3 years ago
15

During an adiabatic process, an ideal gas does 25 j of work. what is the change in the internal (thermal) energy of the gas duri

ng this process?
Physics
1 answer:
Kitty [74]3 years ago
8 0

The change in the internal energy of the gas during the process is 25 J.

Explanation:

In an adiabatic process, no heat is gained or lost by the system. According to the first law of thermodynamics,

Q= dU + dW

Here, Q is heat gained or lost by the system,

dU is the change in the internal energy of the system,

dW is the work done,

As the process is adiabatic, Q=0 we get,

dU= ₋ dW = ₋ 25 J

The negative sign shows that there is a decrease in the temperature of the system.

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Radda [10]

6.  Since we are not sure if the person in the question is actively lifting the crate, we have to determine the downwards force of the crate due to gravity and compare it to the normal force.  

F = ma

F = (15.3)(-9.8)

F = -150N

Since the downwards force of the crate is equivalent to the normal force, it means the person is applying no force in picking up the object.  So to pick up a 150N object from scratch, you would have to exert more force than the weight of the object, so the answer is 294N.


7.  Same idea as question 2.  

First determine the weight of the object:

F = ma

F = (30)(-9.8)

F = -294N

The crate in question is not moving, so the magnitudes of the forces in the upwards and downwards direction has to equal to 0.

-294 + 150N + x = 0

x = 144N  

So the person is exerting 144 N.


10.  First find the force of block B to the right due to its acceleration:

F = ma

F = (24)(0.5)

F = 12N

So block B is moving 12N to the right relative to block A due to block A's movement to the left.  However, block A is being applied a much greater force and is moving quicker to the left than block B is moving to the right of bock A.  The force that is causing block B to experience the lower relative force to the right is because of the friction.  To find the friction:

The sum of the forces in the leftward and rightward direction for block B must equal 12N.

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3 years ago
A 100 kg cart goes around the inside of a vertical loop of a roller coaster. The radius of the loop is 3 m and the cart moves at
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200 N

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3 years ago
What is the magnetic flux density (B-field) at a distance of 0.36 m from a long, straight wire carrying a current of 3.8 A in ai
olga nikolaevna [1]

Answer:

The magnetic flux density is 2.11\times10^{-6}\ T

Explanation:

Given that,

Distance = 0.36 m

Current = 3.8 A

We need to calculate the magnetic flux density

Using formula of magnetic field

B =\dfrac{\mu_{0}I}{2r}

Where,

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Put the value into the formula

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Hence, The magnetic flux density is 2.11\times10^{-6}\ T

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