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Zina [86]
3 years ago
6

A ball is thrown straight up into the air, with an initial speed of 18.2 m/. How far has it gone after 1.00 s?

Physics
1 answer:
dalvyx [7]3 years ago
6 0
The distance that the ball was able to travel at a given time is calculated through the equation,

    d = Vot + (1/2)(g)(t²)

Then, we substitute the known values from the given above,

   d = (-18.2 m/s)(1 s) + 0.5(-9.8 m/s²)(1 s)²
     d= -23.1 m

Thus, the distance traveled by the ball after an hour is equal to 23.1 m

<em>ANSWER: 23.1 m</em>
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Read 2 more answers
1. There is a famous intersection in Kuala Lumpur, Malaysia, where thousands of vehicles pass each hour. A 750 kg Tesla Model S
tigry1 [53]

Solution :

Let the positive x-axis is along the East and the positive y direction is along the north.

Given :

Mass of the Tesla car, m_1 = 750 \ kg

Mass of the Ford car, m_2 = 1250 \ kg

Now let the initial velocity of Tesla car in the south direction be = -v_1j

The initial momentum of Tesla car, p_1 = -750 \ v_1

Let the initial velocity of Ford car in the east direction be = v_2 \ i

So the initial momentum of the Ford car is p_2=1250\ v_2 \ i

Therefore, the initial velocity of both the cars is p_i = p_1+p_2

                                                                  =1250 \ v_2 \ i - 750\ v_1 \ j

Now the final velocity of both the cars is v = 18 \ m/s

So the vector form is :

v = 18\cos 32\ i-18 \sin 32 \ j

  = 15.26 \ i - 9.54 \ j

Therefore the momentum after the accident is

p_f=(m_1+m_2) \times v

    =(750+1250) \times (15.26 \ i - 9.54 \ j)

    = 30520\ i -19080\ j

According to the law of conservation of momentum, we know

p_i = p_f

1250 \ v_2 \ i - 750\ v_1 \ j  = 30520\ i -19080\ j

1250 \ v_2 = 30520

v_2=24.4 \ m/s

From, 750\ v_1 = 19080

We get, v_1=25.4 \ m/s

Therefore the speed of Tesla car before collision = 25.4 m/s

The speed of ford car before collision = 24.4 m/s

6 0
3 years ago
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