Answer: It has one solution. The solution is (x,y) = (-4,-3)
Add up the equations doing so straight down
x + -x = 0x = 0 so the x terms go away
2y + 2y = 4y
-10 + (-2) = -12
We end up with 4y = -12 so y = -3 after you divide both sides by 4. Use this y value to find the value of x
x+2y = -10
x + 2(-3) = -10
x - 6 = -10
x = -10+6
x = -4
The single solution is (x,y) = (-4,-3)
As a check, plug this solution into each equation to see if you get a true statement or not. Let's do so with the first equation
x+2y = -10
-4 + 2(-3) = -10
-4 - 6 = -10
-10 = -10 .... true
and then the second equation
-x+2y = -2
-(-4) + 2(-3) = -2
4 - 6 = -2
-2 = -2 .... true
both equations are true, so the solution is confirmed
Answer:
C. (36337.32, 48968.68)
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42653 - 6315.68 = 36337.32.
The upper end of the interval is the sample mean added to M. So it is 42653 + 6315.68 = 48968.68.
So the correct answer is:
C. (36337.32, 48968.68)
Answer:
2
Step-by-step explanation:
![f( \frac{1}{4} ) = {16}^{ \frac{1}{4} } = \sqrt[4 ]{16} = 2](https://tex.z-dn.net/?f=f%28%20%5Cfrac%7B1%7D%7B4%7D%20%29%20%3D%20%20%7B16%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%3D%20%20%20%5Csqrt%5B4%20%5D%7B16%7D%20%20%3D%202)
That's it, hope you enjoyed it.
The median is nine (9). You add each number up, and then you divide by the amount of numbers you have.
The mean is 9.83 according to my calculations.
<span>Assuming that Josh throws the discus 36 times, the expected value of y will be the length each discus reaches for each throw all added together. Specifically, it will be discus throw one, plus discus throw two -- all the way to discus throw thirty-six. Adding all of those throws together will provide the expected value of Y.</span>
