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tresset_1 [31]
3 years ago
10

(2x^4 + 3x^3 – 5x - 19)+(x^2 + 1)

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

2x  4  +3x 3  +x  2  −5x−18

Step-by-step explanation:

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Answer:

The answer is 31 pennies

Step-by-step explanation:

we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.

The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:

1) factor: 5 (+1) = 6

6 ÷ 2 = 3 remainder 0

6 ÷ 3 = 2 remainder 0

since there is a remainder of 0, when divided by 3, 6 is wrong

2) factor; 10 (+1) = 11

11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer

3) factor : 15 (+1) = 16

16 ÷ 2 = 8 remainder 0 ( 16 is  not the correct answer

4) factor : 20(+1) = 21

21 ÷ 3 = 7 remainder 0 ( 21 is wrong)

5) factor : 25(+1) = 26

26 ÷ 2 = 13 remainder 0 ( 26 is wrong)

6) factor : 30(+1) = 31

31 ÷ 2 = 15 Remainder 1

31 ÷ 3 = 10 Remainder 1

31 ÷ 5 = 6 Remainder 1

since all three divisors give a remainder of 1, the correct answer is 31

Therefore you have 31 pwnnies

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Step-by-step explanation:

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A

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