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o-na [289]
3 years ago
15

Math Homework Number 49

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0
[((2 / 75.5) - 3) * 2]3 (make 3 an exponent.)
solong [7]3 years ago
3 0
She is correct it is 3exsponet
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Which equation represents an exponential function with an initial value of 500? f(x) = 100(5)x f(x) = 100(x)5 f(x) = 500(2)x f(x
Evgen [1.6K]

Answer:

The answer is

Step-by-step explanation:

C. f(x) = 500(2)^x

2020

3 0
3 years ago
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A triangle has a perimeter of 48 feet. If the three sides of the triangle are n, 4n−2, and 4n−4, what is the length of each side
alexdok [17]

Answer:

6; 22; 20 (ft.)

Step-by-step explanation:

1) if the length of the each side are: n; 4n-2 and 4n-4, then the expression of the perimeter can be written: P=n+4n-2+4n-4 or P=9n-6.

2) if according to the condition perimeter is 48 (ft.), then

9n-6=P; ⇔ 9n-6=48; n=6.

3) if n=6, then the required lengths of the sides are:

n=6 (ft.);

4n-2=22 (ft.);

4n-4=20 (ft.)

3 0
2 years ago
The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x. step by step explanation.​
mars1129 [50]

Answer:

The area of the rectangle in terms of 'x' = 13x

Step-by-step explanation:

  • Perimeter = 30 cm
  • Length = x cm

Using the perimeter formula to find the width w.

P=2(l+w)

P = 2l + 2w

2w = P-2l

Dividing both sides by 2

w\:=\:\frac{P}{2}-2

as P = 30 cm

w\:=\:\frac{30}{2}-2

w\:=\:15-2

w = 13 cm

Using the formula of the rectangle area

A = wl

substitute w = 13 and l = x in the formula

A=13\times \:x

A = 13x

Therefore, the area of the rectangle in terms of 'x' = 13x

7 0
3 years ago
You decide that you would like to buy a new notebook computer. You currently have $50 that you earned from babysitting. You can
Paraphin [41]
Okay? Whats the point? If You're trying to find out how long it would take then you would have to make $500 so 45 more hours until you can get it.
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3 years ago
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Volume of the cone?
ratelena [41]

Answer:

209.44

Step-by-step explanation:

V=pie r square h by 3

=

π

r

2

h

3

8 0
3 years ago
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