First, we write the equation of formation of potassium chloride from chlorine:
2K + Cl₂ → 2KCl
Each mole of Cl₂ produces two moles of KCl
Therefore, the conversion factor is:
Moles of chlorine = 2 x moles of potassium chloride
Answer:
The volume of the gas at a pressure of 65.0 kPa would be 363 mL
Explanation:
Boyle's Law is a gas law that relates the pressure and volume of a certain amount of gas, without temperature variation, that is, at constant temperature.
Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. In other words, the product P · V remains constant at the same temperature:
P*V=k
Being P1 and V1 the pressure and volume in state 1 and P2 and V2 the pressure and volume in state 2 are fulfilled:
P1*V1=P2*V2
In this case:
- P1= 45 kPa= 45,000 Pa (being 1 kPa=1,000 Pa)
- V1= 525 mL= 0.525 L (being 1 L=1,000 mL)
- P2= 65 kPa= 65,000 Pa
- V2= ?
Replacing:
45,000 Pa* 0.525 L= 65,000 Pa*V2
Solving:
![V2=\frac{45,000 Pa* 0.525 L}{65,000 Pa}](https://tex.z-dn.net/?f=V2%3D%5Cfrac%7B45%2C000%20Pa%2A%200.525%20L%7D%7B65%2C000%20Pa%7D)
V2=0.363 L=363 mL
<u><em>The volume of the gas at a pressure of 65.0 kPa would be 363 mL</em></u>
Answer:
CH3(CH2)8CH3 > CH3CH2CH2CH3 > CH3CH3 (Option f)
Explanation:
Larger and heavier atoms and molecules exhibit stronger dispersion forces than smaller and lighter ones. In a larger atom or molecule, the valence electrons are, on average, farther from the nuclei than in a smaller atom or molecule. They are less tightly held and can more easily form temporary dipoles.
CH3CH3 has a molar mass of 30.07 g/mol
CH3(CH2)8CH3 has a molar mass of 142.28 g/mol
CH3CH2CH2CH3 has a molar mass of 58.12 g/mol
CH3(CH2)8CH3 > CH3CH2CH2CH3 > CH3CH3 (Option f)
Answer:
D) The sun is a burning ball of gas, and the moon revolves around a planet.
Explanation:
Unlike what Jack has written in his table, the sun is comprised of 92% gas and has no definable rocky layer or even dust. The moon revolves specifically around the Earth.
Answer:- Molecular formula of the compound is
.
Solution:- An empirical formula and molar mass of the compound is given and we are asked to calculate it's molecular formula. First of all we calculate the empirical formula mass and then divide the molar mass by empirical formula mass to find out the number of empirical formula units.
Empirical formula is multiplied by the number of empirical formula units to get the molecular formula.
Empirical formula mass = 2(12.01) + 3(1.01)
= 24.02 + 3.03
= 27.05
number of empirical formula units = ![\frac{54.091}{27.05}](https://tex.z-dn.net/?f=%5Cfrac%7B54.091%7D%7B27.05%7D)
= 2
So, molecular formula of the compound = ![2(C_2H_3)](https://tex.z-dn.net/?f=2%28C_2H_3%29)
= ![C_4H_6](https://tex.z-dn.net/?f=C_4H_6)