The given statement is true .
<h3>What is Rutherford’s gold foil experiment?</h3>
- A piece of gold foil was hit with alpha particles, which have a favorable charge. Most alpha particles went right around. This showed that the gold particles were mostly space.
- The Rutherford gold leaf investigation supposed that most (99%) of all the mass of an atom is in the middle of the atom, that the nucleus is very small (105 times small than the length of the atom) and that is positively captured.
- For the distribution experiment, Rutherford enjoyed a metal sheet that could be as thin as practicable. Gold is the most malleable of all known metals. It can easily be converted into very thin sheets. Hence, Rutherford established a gold foil for his alpha-ray scattering experimentation.
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Answer:
1188.0 mL.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>V₁T₂ = V₂T₁
</em>
V₁ = 900 mL, T₁ = 27.0°C + 273 = 300.0 K.
V₂ = ??? mL, T₂ = 123.0°C + 273 = 396.0 K.
<em>∴ V₂ = V₁T₂/T₁ </em>= (900 mL)(396 K)/(300.0 K) = <em>1188.0 mL.</em>
The density of CO gas if 0.196g occupies a volume of 100mL is0.00196g<span>mL or 0.00196 grams per milliliter</span>
<span>A </span>sample<span> of </span>grape juice has<span> a </span>hydroxide ion concentration<span> of </span>1.4<span> × </span>10-10 M<span> What is the</span>concentration<span> of </span>hydronium ion<span>? __x 10 x^-5 </span>M. Ask for details; Follow ... Unlock Verified Answers andget<span> help from subject experts. ... The relation between </span>hydroxide ion<span> (OH-) and </span>hydronium ion<span> (H3O+) is given by many things</span>
The element used in advertising signs is neon.
