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Alex Ar [27]
3 years ago
8

Look at the reaction below.

Chemistry
2 answers:
HACTEHA [7]3 years ago
6 0
The acid is H2SO4(an)
solong [7]3 years ago
4 0

Answer: H_2SO_4 is a acid.

Explanation: Acid is anything which donates H^+ ions and in this reaction H_2SO_4 is donating H^+ ions, therefore it is considered as an Acid.

This reaction is a type of reaction an acid undergoes that is when an acid reacts with metal it produces metal salt and hydrogen gas

2HA(aq)+2M(s)\rightarrow 2MA(aq)+H_2(g)

and the given reaction is

H_2SO_4(aq)+Mg(s)\rightarrow MgSO_4(aq)+H_2(g)

where, H_2SO_4 = Acid

Mg = metal

MgSO_4 = Metal Salt

H_2 = Hydrogen gas

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A methanol-water mixture is to be flash distilled at 1 atm. If the feed is 25 mole %methanol, what are the liquid and vapor comp
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Explanation:

Given that:

The distillation is carried out at a pressure of 1 atm

The feed harbors 25% mole of methanol (z)

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Using the total mole balance for the distillation column.

Fz = Lx + Vy

where;

F = amount of feed

z = mole fraction of ethanol (in feed)

L = amount of liquid product out of the column

V = amount of vapor product out of the column

x = mole fraction of methanol out of the liquid

y  = mole fraction of methanol out of the vapor.

SO;

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If all the feed is vaporized, then the vapor will likely have the same composition as the feed.

(b)

If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.

(c)

If 1/3 of the feed is vaporized; then 2/3 of the feed is at the bottom.

The balance equation would be:

Fz = (\dfrac{2}{3}F) x + (\dfrac{1}{3}F)y \\ \\ z = \dfrac{2}{3}x+\dfrac{1}{3}y

Replacing z = 0.25; we have:

0.25 = \dfrac{2}{3}x+\dfrac{1}{3}y

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(d)

If 2/3 of the feed is vaporized;

Then:

Fz = (\dfrac{1}{3}F) x + (\dfrac{2}{3}F)y \\ \\ z = \dfrac{1}{3}x+\dfrac{2}{3}y

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0.25 = \dfrac{1}{3}x+\dfrac{2}{3}y

0.75 = x + 2y

6 0
2 years ago
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