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3 years ago

Look at the reaction below.

Chemistry

2 answers:

HACTEHA [7]3 years ago

6 0

The acid is H2SO4(an)

solong [7]3 years ago

4 0

Answer: $H_2SO_4$ is a acid.

Explanation: Acid is anything which donates $H^+$ ions and in this reaction $H_2SO_4$ is donating $H^+$ ions, therefore it is considered as an Acid.

This reaction is a type of reaction an acid undergoes that is when an acid reacts with metal it produces metal salt and hydrogen gas

$2HA(aq)+2M(s)\rightarrow 2MA(aq)+H_2(g)$

and the given reaction is

$H_2SO_4(aq)+Mg(s)\rightarrow MgSO_4(aq)+H_2(g)$

where, $H_2SO_4$ = Acid

Mg = metal

$MgSO_4$ = Metal Salt

$H_2$ = Hydrogen gas

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How many moles of nitrogen are in 2.0×10−2mole of quinine?

galben [10]

Answer: 4 x 10 ∧-2 moles of nitrogen.

Explanation:

The chemical formular for quinine is ; C20 H24 N2 O2

As can be seen from the chemical formular;

1 mole of quinine contains 2 moles of Nitrogen

Thus; 2.0 x 10 ∧-2 moles of quinine would contain

2.0 x 10 ∧-2 x 2 = 4 x 10 ∧-2 moles of nitrogen.

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3 years ago

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Soloha48 [4]

Answer:

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Explanation:

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3 years ago

If 54 g of Al reacted with 160 g of O2, find out the weight of product

Oxana [17]

Answer:

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3 years ago

A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr

sertanlavr [38]

Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.947 atm

$P_2$ = final pressure of gas = 0.987 atm

$V_1$ = initial volume of gas = 150 ml

$V_2$ = final volume of gas = 144 ml

$T_1$ = initial temperature of gas = $25^0C=(25+273.15)K=298.15K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}$

$T_2=298.31K=(298.31-273.15)^0C=25.16^0C$

The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

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jenyasd209 [6]

Answer:

Explanation:

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