1. Create a diagram of your electroplating apparatus (an electrolytic cell). Then submit your drawing with the following terms l
abeled correctly.
• anode
• cathode
• copper strip
• battery
• positive terminal
• negative terminal
• place where oxidation occurs
• place where reduction occurs
• electrolyte solution
• coin (or nail)
• direction of electron flow
• anode
• cathode
• copper strip
• battery
• positive terminal
• negative terminal
• place where oxidation occurs
• place where reduction occurs
• electrolyte solution
• coin (or nail)
• direction of electron flow
1 answer:
A picture of the electroplating apparatus can be found attached. The nail (cathode) is completely submerged and that is where reduction happens. In the other side, the copper strip is (anode) where oxidation happens. The electron flow happens from the anode to the cathode. The positive charge of the battery is attached to the anode while the negative side is attached to the cathode.
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Amines are derivatives of Ammonia (NH₃) in which atleast one hydrogen atom is replaced by an alkyl group. Amines are further classifies as;
Primary Amines:
In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.
Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.
Tertiary Amines:
In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.
Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.
Primary Amines:
In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.
Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.
Tertiary Amines:
In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.
Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.
Answer:
<em><u>The molarity of the CoBr2•4H2O solution is 7.64 × 10-2 M</u></em>
Explanation:
Cobalt (II) bromide tetrahydrate
• Cobalt - A transition metal with Roman numeral (II) → charge: +2 → Co2+
• Bromide - anion from group 7A → -1 charge → symbol: Br-
• Tetrahydrate- tetra- means 4 and hydrate is H2O
The chemical formula of the compound is: CoBr2•4H2O
We then need to determine the number of moles of CoBr2•4H2O since this is the only information missing for us to find molarity. Notice that the volume of the solution is already given.
We’re given the mass of CoBr2•4H2O. We can use the molar mass of CoBr2•4H2O4 to find the moles.
•The molar mass of CoBr2•4H2O is:
CoBr2•4H2O
1 Co x 58.93 g/mol Co = 58.93 g/mol
2 Br x 79.90 g/mol Br = 159.80 g/mol
8 H x 1.008 g/mol H = 8.064 g/mol
4 O x 16.00 g/mol O = 64.00 g/mol
________________________________________
Sum = <u>290.79 g/ mo</u>
The moles of CoBr2•4H2O is:
= 10.0 g CoBr2•4H2O x
= <u>0.0344 mol CoBr2•4H</u>
We know that the volume of the solution is 450 mL.
We can now calculate for molarity:
Convert mL to L → 1 mL = 10-3 L
Formula:
Molarity (M)= Mole of solute / Liters of solution
= 0.0344 mol CoBr2•4H / 450 mL x 1 ml / 10^ -3 L
= 0.0764
= 7.64 × 10-2 mol/L