1. Create a diagram of your electroplating apparatus (an electrolytic cell). Then submit your drawing with the following terms l
abeled correctly.
• anode
• cathode
• copper strip
• battery
• positive terminal
• negative terminal
• place where oxidation occurs
• place where reduction occurs
• electrolyte solution
• coin (or nail)
• direction of electron flow
• anode
• cathode
• copper strip
• battery
• positive terminal
• negative terminal
• place where oxidation occurs
• place where reduction occurs
• electrolyte solution
• coin (or nail)
• direction of electron flow
1 answer:
A picture of the electroplating apparatus can be found attached. The nail (cathode) is completely submerged and that is where reduction happens. In the other side, the copper strip is (anode) where oxidation happens. The electron flow happens from the anode to the cathode. The positive charge of the battery is attached to the anode while the negative side is attached to the cathode.
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The number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.
<h3>What are moles?</h3>A mole is defined as 6.02214076 × of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Given data:
Moles of hydrochloric acid = 0.385 mol
Mass of chlorine gas =?
Chemical equation:
4HCl + O₂ → 2Cl₂ + 2H₂O
Now we will compare the moles of Cl₂ with HCl.
HCl : Cl₂
4 : 2
0.385 : 2÷4× 0.385 = 0.1925 mol
Oxygen is present in excess that's why the mass of chlorine produced depends upon the available amount of HCl.
Mass of Cl₂ :
Mass of Cl₂ = moles × molar mass
Mass of Cl₂ =0.1925 mol × 71 g/mol
Mass of Cl₂ = 13.6675 g
Hence, the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.
Learn more about moles here:
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