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Lemur [1.5K]
3 years ago
5

The radius of a strontium atom is 215 pm. How many strontium atoms would have to be laid side by side to span a distance of 4.19

mm?
Chemistry
1 answer:
Solnce55 [7]3 years ago
8 0

Answer:

0.97 ×  10⁹ strontium atoms

Explanation:

if       1 pm is equal with 10⁻⁹ mm

then  215 pm are equal to X mm

X = (215 ×  10⁻⁹) / 1 = 215 ×  10⁻⁹ mm

Now the diameter of the strontium atom is twice the radius:

diameter = 215 ×  10⁻⁹ × 2 = 430 ×  10⁻⁹ mm

if           1 strontium atom have a diameter of 430 ×  10⁻⁹ mm

then      X strontium atom are needed to be laid said by side to span a distance of 419 mm

X = (419 × 1) / (430 ×  10⁻⁹) mm = 0.97 ×  10⁹ strontium atoms

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5 0
3 years ago
What is the final pressure (expressed in atm) of a 3.05 L system initially at 724 mm Hg and 298 K, that is compressed to a final
maksim [4K]

Hey there!:

V1 = 3.05 L

V2 = 3.00 L

P1 = 724 mmHg

P2 = to be calculated

T1 = 298 K

T2 = 273 K

Therefore:

P1*V1  / T1  = P2*V2 / T2

P2 = ( P1*V1 / T1  )   * T2 / V2

P2 = 724 * 3.05 * 273 / 298 * 3.00

P2 = 602838.6 / 894

P2 = 674.31 mmHg

1 atm ----------- 760 mmHg

atm ------------- 674.31 mHg

= 674.31 * 1 / 760

= 0.887 atm

Hope this helps!

5 0
4 years ago
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Alexxx [7]

Answer:

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Explanation:

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6 0
3 years ago
What is the molar concentration of H2SO4 in a solution made by reacting 188.9 mL of 2.086 M H2SO4 with 269.3 mL of 0.4607 M NaOH
MrRissso [65]

Answer:

0.7246 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 2.086 M

Volume = 188.9 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 188.9×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=2.086 \times {188.9\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.39405 moles

For NaOH :

Molarity = 0.4607 M

Volume = 269.3 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 269.3×10⁻³ L

Thus, moles of NaOH :

Moles=0.4607 \times {269.3\times 10^{-3}}\ moles

Moles of NaOH  = 0.1241 moles

According to the given reaction:

H_2SO_4_{(aq)}+2NaOH_{(aq)}\rightarrow Na_2SO_4_{(aq)}+2H_2O_{(aq)}

1 moles of H_2SO_4 react with 2 moles of NaOH to form 1 mole of sodium sulfate.

Thus,

2 moles of NaOH react with 1 mole of H_2SO_4

1 mole of NaOH react with 1/2 mole of H_2SO_4

0.1241 moles of NaOH react with (1/2)×0.1241 mole of H_2SO_4

Moles of H_2SO_4 that got reacted = 0.06205 moles

Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles

Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L

Concentration of H_2SO_4 :

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{H_2SO_4}=\frac{0.332}{458.2\times 10^{-3}}

<u>Concentration of H_2SO_4 = 0.7246 M</u>

5 0
4 years ago
What's the ratio of atoms of each element in the compound ammonium monohydrogen phosphate (NH4)2HPO4?
GREYUIT [131]
So there are 2 N, 9 H, 1 P and 4 O. so N:H:P:O is 2:9:1:4? i think
4 0
3 years ago
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