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Lemur [1.5K]
3 years ago
5

The radius of a strontium atom is 215 pm. How many strontium atoms would have to be laid side by side to span a distance of 4.19

mm?
Chemistry
1 answer:
Solnce55 [7]3 years ago
8 0

Answer:

0.97 ×  10⁹ strontium atoms

Explanation:

if       1 pm is equal with 10⁻⁹ mm

then  215 pm are equal to X mm

X = (215 ×  10⁻⁹) / 1 = 215 ×  10⁻⁹ mm

Now the diameter of the strontium atom is twice the radius:

diameter = 215 ×  10⁻⁹ × 2 = 430 ×  10⁻⁹ mm

if           1 strontium atom have a diameter of 430 ×  10⁻⁹ mm

then      X strontium atom are needed to be laid said by side to span a distance of 419 mm

X = (419 × 1) / (430 ×  10⁻⁹) mm = 0.97 ×  10⁹ strontium atoms

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Calculate how many grams would be required to prepare 600. 0 ml of 0. 150 m of naf? molar mass of naf is 41. 9 g/mo
marta [7]

Considering the definition of molarity and molar mass, the mass of NaF required is 3.771 grams.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liters}.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3 /><h3>Mass of NaF required</h3>

In this case, you know:

  • molarity= 0.15 M= 0.15 \frac{moles}{L}
  • number of moles= ?
  • volume= 600 mL= 0.6 L

Replacing in the definition of molarity:

0.15\frac{moles}{L} =\frac{number of moles}{0.6 L}

Solving:

0.15 \frac{moles}{L} × 0.6 L= number of moles

<u><em>0.09 moles= number of moles</em></u>

The molar mass of NaF is 41. 9 g/mol. So, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 41.9 grams, 0.09 moles of the compound contains how much mass?

mass=\frac{0.09 molesx41.9 grams}{1 mole}

<u><em>mass= 3.771 grams</em></u>

Finally, the mass of NaF required is 3.771 grams.

Learn more about

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

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