Answer:
C is the answer hoped I helped you have a awesome day by
Hey there!:
V1 = 3.05 L
V2 = 3.00 L
P1 = 724 mmHg
P2 = to be calculated
T1 = 298 K
T2 = 273 K
Therefore:
P1*V1 / T1 = P2*V2 / T2
P2 = ( P1*V1 / T1 ) * T2 / V2
P2 = 724 * 3.05 * 273 / 298 * 3.00
P2 = 602838.6 / 894
P2 = 674.31 mmHg
1 atm ----------- 760 mmHg
atm ------------- 674.31 mHg
= 674.31 * 1 / 760
= 0.887 atm
Hope this helps!
Answer:
0.7246 M
Explanation:
Considering:
Or,
Given :
For
:
Molarity = 2.086 M
Volume = 188.9 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 188.9×10⁻³ L
Thus, moles of
:
Moles of
= 0.39405 moles
For NaOH :
Molarity = 0.4607 M
Volume = 269.3 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 269.3×10⁻³ L
Thus, moles of NaOH :
Moles of NaOH = 0.1241 moles
According to the given reaction:
1 moles of
react with 2 moles of NaOH to form 1 mole of sodium sulfate.
Thus,
2 moles of NaOH react with 1 mole of 
1 mole of NaOH react with 1/2 mole of 
0.1241 moles of NaOH react with (1/2)×0.1241 mole of 
Moles of
that got reacted = 0.06205 moles
Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles
Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L
Concentration of
:
<u>Concentration of
= 0.7246 M</u>
So there are 2 N, 9 H, 1 P and 4 O. so N:H:P:O is 2:9:1:4? i think