All categories

3 years ago

How many times greater. Is the value of 8 in 18,272 than the value of 8 in 17,282

Mathematics

1 answer:

PIT_PIT [208]3 years ago

3 0

1,8272 --- 8,000

17,282 --- 80

8,000÷80=100 times greater

You might be interested in

Compute using long division: 1,234÷68

Kruka [31]

Answer:

Quotient = 18

Remainder = 10

Step-by-step explanation:

1234/68

=> 68 x 1 = 68

=> 123 - 68 = 55

=> Take the 4 down

=> 554/68

=> 68 x 8 = 544

=> 554 - 544 = 10

So, the quotient = 18.

Remainder = 10

4 0

3 years ago

Which is the logarithmic form of 4^5 = 1024

leva [86]

Answer:

$Log_41024=5$

Step-by-step explanation:

The change of form formula (exponential to logarithm) is:

$a^x=b\\Log_ab=x$

Looking at the problem given, we can simply write the logarithmic form as:

$4^5=1024\\Log_41024=5$

This is the answer.

3 0

3 years ago

Violet's Botanical Garden produced flowers throughout the year. A graph demonstrating how many flowers she produced over a 12-mo

Lady bird [3.3K]

Answer:

The domain represents a 12-month period of flower production

Step-by-step explanation:

The <em>domain</em> is <em>the horizontal extent of the graph</em>. Both the problem statement and the graph itself tell you that is a 12 month time period.

7 0

3 years ago

Read 2 more answers

What is the value of the fourth term in a geometric sequence for which a1 = 30 and r = 1/2?

Pani-rosa [81]

Answer: The required fourth term of the geometric sequence is $\dfrac{10}{9}.$

Step-by-step explanation: We are given to find the value of the fourth term in a geometric sequence with first term and common ratio as follows :

$a(1)=30,~~~~~r=\dfrac{1}{2}.$

We know that

the n-th term of a geometric sequence with first term a1 and common ratio r given by

$a(n)=a(1)r^{n-1}.$

Therefore, the fourth term of the given geometric sequence will be

$a(4)=a(1)r^{4-1}=30\times r^3=30\times\left(\dfrac{1}{3}\right)^3=\dfrac{30}{27}=\dfrac{10}{9}.$

Thus, the required fourth term of the geometric sequence is $\dfrac{10}{9}.$

7 0

3 years ago

Read 2 more answers

The area of a square garden is 1681 square feet. What are the dimensions of the garden?

12345 [234]

Divide 1681 by 4 which is about 420.25 feet for length

6 0

3 years ago

Read 2 more answers