Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.
Explanation:
Given: = 2.25 L, = 9.0 mol
= 1.85 L, = ?
Formula used to calculate the moles of helium are as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.
Answer:
Nsc=30
Explanation:
The solid angle subtended by the counter is
d=0.1mm2/(1cm)2=(10)3 sr
d=(10)10x10.5gcm3x10-4cm/108x1.6610x10-24gx0.510-24cm2x10-3=30
What is the mass, in grams, of 0.00948\,\text {mol}0.00948mol0, point, 00948, start text, m, o, l, end text of phosphoric acid?
ANEK [815]
Answer:
0.929g
Explanation:
The following were obtained from the question.
Number of mole of phosphoric acid (H3PO4) = 0.00948mol.
Mass of H3PO4 =?
The mass in grams of phosphoric acid (H3PO4) can be obtained as follow:
Number of mole of H3PO4 = 0.00948mol.
Molar Mass of H3PO4 = (3x1) + 31 + (16x4) = 3 + 31 + 64 = 98g/mol
Mass of H3PO4 =?
Mass = number of mole x molar Mass
Mass of H3PO4 = 0.00948 x 98
Mass of H3PO4 = 0.929g
C. During a storm, a river is carrying a lot more sediment than during a low flow period