There are 2071.4662 grams of glucose in 11.5 moles.
Per 1 mole there are 180.15588 grams of glucose. 180.5588 x 11.5 =2076.4262
Answer:
Passive Transport
Explanation:
The three examples of passive transport are
Diffuison
Osmosis
facilated diffuison
So the answer can be A or B
The solution to the problem is as follows:
<span>a)
C + O2 = CO2
Molar mass CO2 = 44 g/mol
3.67 g CO2 * 1 mol / 44 g =
=0.0834 mol CO2 = 0.0834 mol C
I hope my answer has come to your help. God bless and have a nice day ahead!
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It should just be one for it to be balanced.
It is recycled. Copper, like other metals it melted back down for farther use in other products and structures.