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Likurg_2 [28]
3 years ago
14

The differential cross section for scattering 6.5-MeV alpha particles at 120° off a silver nucleus is about 0.5 barns/sr. If a t

otal of 10 10 alphas impinge on a silver foil of thickness 1 itm and if we detect the scattered particles using a counter of area 0.1 mm 2 at 120° and 1 cm from the target, about how many scattered alphas should we expect to count? (Silver has a specific gravity of 10.5, and atomic mass of 108.) 14.12 ***
Chemistry
1 answer:
Burka [1]3 years ago
8 0

Answer:

Nsc=30

Explanation:

The solid angle subtended by the counter is

d=0.1mm2/(1cm)2=(10)3 sr

d=(10)10x10.5gcm3x10-4cm/108x1.6610x10-24gx0.510-24cm2x10-3=30

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Using the system of rules for naming binary acids and naming other binary covalent molecules​
ANEK [815]

Answer:

Atoms

Explanation:

This is also a form of molucules

3 0
3 years ago
HELPPPP ASAPPPPP IN NEED IT NOWWWW<br> PICK ON OF THE BLUE ONES<br> ITS NOT IN
evablogger [386]

It's gonna be Rb. The rule is that the lower it is and the closer it is to the left, the more reactive it will be.

Why left? Because their valence decreases, and the atom has a stronger desire to bond with other atoms. Alkali metals are considered the MOST reactive group in the periodic table, followed by AEM (alkaline earth metals). Noble gases are the least reactive because their valence's are full and they don't need 2 bond with anyone else. That's why artifacts are placed in noble-gas rich environments; so that they don't ruin and reactions don't occur (the declaration of independence is sealed in a helium container for that purpose)

Why down? Because there are more electron shells, resulting in a greater distance between the valence electrons and the nucleus. This reduces the attraction.



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3 0
4 years ago
In a titration of nitrous acid with NaOH, the pH of the solution is 3.14 when the moles of HNO2 and the moles of NO2-- are equal
jonny [76]

Answer:

Ka=3.98x10^{-4}

Explanation:

Hello there!

In this case, since the modelling of titration problems can be approached via the Henderson-Hasselbach equation to set up a relationship between pH, pKa and the concentration of the acid and its conjugate base, we can write:

pH=pKa+log(\frac{[NO_2^-]}{[HNO_2]} )

Whereas the pH is given as 3.14 and the concentrations are the same, that is why the pH would be equal to the pKa as the logarithm gets 0 (log(1)=0); thus, we can calculate the Ka via:

Ka=10^{-pKa}=10^{-3.14}\\\\Ka=3.98x10^{-4}

Best regards!

4 0
3 years ago
The temperature of evaporation is much higher for water than for alcohol. Without knowing more about the chemistry of alcohol, w
Valentin [98]

Answer:

Fewer hydrogen bonds form between alcohol molecules. As a result, less heat is needed for alcohol molecules to break away from solution and enter the air.

Explanation:

Hydrogen bonding is a kind of intermolecular interaction that occurs when hydrogen is bonded to a highly electronegative atom.

Both water and alcohols exhibit hydrogen bonding. However, alcohols exhibit fewer hydrogen bonds than water.

As a result of this, the temperature of evaporation is much higher for water than for alcohol because hydrogen bonds hold water molecules more closely than alcohol molecules are held.

8 0
3 years ago
Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that
svetlana [45]

Answer : The value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

Explanation :

Formula used :

D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )

where,

D = diffusion coefficient = ?

D_o = 5.6\times 10^{-5}m^2/s

Q_d = 177kJ/mol

R = gas constant = 8.314 J/mol.K

T = temperature = 547^oC=273+547=820K

Now put all the given values in the above formula, we get:

D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )

D=2.97\times 10^{-16}m^2/s

Thus, the value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

6 0
3 years ago
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