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Oduvanchick [21]
3 years ago
9

Students were asked to place a mint in their mouths and determine how long it took for the mint to dissolve. The

Chemistry
1 answer:
saveliy_v [14]3 years ago
4 0

B. The time is likely between 40 - 80 seconds.

<u>Explanation:</u>

One group of students were asked to leave a whole mint in their  mouth, not moving it around, and let it dissolve, which takes very long time to dissolve since there is lower frequency of collision among the saliva particles and mint.

Another group swirled a whole mint around in their mouths, so the frequency of collision between the saliva and the mint particles increases, there by increase in dissolving capacity, but the timing will be lesser when compared to other groups used mints broken into smaller pieces.

So the time for swirling is likely between 40 - 80 seconds.

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What is the molarity of a solution that contain 1.1 miles of lithium in 0.5 liters of solution
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The solid product from reaction of sulfuric acid with sucrose is?
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\huge{\mathbb{\tt {QUESTION:}}}

The solid product from reaction of sulfuric acid with sucrose is?

\huge{\mathbb{\tt {ANSWER:}}}

  • Concentrated <u>sulfuric acid</u> is added to sucrose forming carbon, steam and <u>sulfur</u> dioxide.

<h2>--------------------------------------------------------------------------------</h2>

<h3>RELATED TO THE QUESTION </h3>

\huge{\mathbb{\tt {What \:  is \:  solid?:}}}

  • <u>Solid is one of the four fundamental states of matter</u>. The molecules in a solid are closely packed together and contain the least amount of kinetic energy.
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\huge{\mathbb{\tt {What \:  is \:  sulfur \:  acid?}}}

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\huge{\mathbb{\tt{What \:  is \:  sucrose?}}}

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6 0
2 years ago
How mant grams are there in 7.15 x 10^24 molecules of water?
worty [1.4K]

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B. 214.02

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1 mol of water weighs 18.015 gm and contains 6.023 × 10²³ molecules

From question, We have 7.15 × 10²⁴ molecules

Dividing we get (7.15 × 10 ²⁴) ÷ ( 6.023 × 10²³) = 11.871 molecules

Now, Weight of water = 11.871 × 18.015 = 213.85 which is nearer to option B

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