Students were asked to place a mint in their mouths and determine how long it took for the mint to dissolve. The

Chemistry

1 answer:

saveliy_v [14]3 years ago

4 0

B. The time is likely between 40 - 80 seconds.

Explanation:

One group of students were asked to leave a whole mint in their mouth, not moving it around, and let it dissolve, which takes very long time to dissolve since there is lower frequency of collision among the saliva particles and mint.

Another group swirled a whole mint around in their mouths, so the frequency of collision between the saliva and the mint particles increases, there by increase in dissolving capacity, but the timing will be lesser when compared to other groups used mints broken into smaller pieces.

So the time for swirling is likely between 40 - 80 seconds.

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A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

Answer: The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

Explanation:

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$