What do 60 and 60 have in common

Mathematics

2 answers:

notka56 [123]3 years ago

8 0

They are both the same number and also they are positive numbers hope this helps

creativ13 [48]3 years ago

7 0

60 and 60 are both the same number.

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If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$

6 0

3 years ago

Read 2 more answers

In the regual nonagon shown, what is the measure of angle x?

andre [41]

The sum of the interior angles of a polygon is (n-2)*180, n being the number of sides.
a nonagon has nine sides, so the total of interior angles is (9-2)*180=7*180
this is a regular nonagon, so each interior angle has the same degrees:
7*180/9=7*20=140
the exterior angle=180-the interior angle=180-140=40
40 is the correct answer.

4 0

3 years ago

Find the missing probability. P(B)=720,P(A|B)=14 ,P(A∩B)=?

Ivan

Answer:

7/80

Step-by-step explanation:

Given that: P(B) = 7 / 20, P(A|B)= 1 / 4

Bayes theorem is used to mathematically represent the conditional probability of an event A given B. According to Bayes theorem:

$P(A|B)=\frac{P(A \cap B)}{P(B)}$

Where P(B) is the probability of event B occurring, P(A ∩ B) is the probability of event A and event B occurring and P(A|B) is the probability of event A occurring given event B.

$P(A|B)=\frac{P(A \cap B)}{P(B)}\\\\P(A \cap B)=P(A|B)*P(B)\\\\Substituting:\\\\P(A \cap B)=1/4*7/20=7/80\\\\P(A \cap B)=7/80$