We need to solve the speed formula for d. To do so, let's start by moving the number of the left hand side:
![\frac{S}{356} = \sqrt{d}](https://tex.z-dn.net/?f=%20%5Cfrac%7BS%7D%7B356%7D%20%3D%20%5Csqrt%7Bd%7D%20)
Square both sides to get rid of the square root:
![\frac{S^2}{126736} = d](https://tex.z-dn.net/?f=%20%5Cfrac%7BS%5E2%7D%7B126736%7D%20%3D%20d%20)
Now plug the known value of the speed to find the distance:
![d = \frac{140^2}{126736} = \frac{19600}{126736} \approx 0.15465](https://tex.z-dn.net/?f=%20d%20%3D%20%5Cfrac%7B140%5E2%7D%7B126736%7D%20%3D%20%5Cfrac%7B19600%7D%7B126736%7D%20%5Capprox%200.15465%20)
So the closest answer is the last one: d=0.155km
Y’all need to stop doing links!
y’all can get banned.... so yeah okay 623
Ken grew .425 of an inch more than sang because 4/5 is .8 and 3/8 is .375 what you do is you take those two numbers and subtract the smaller one from the bigger one and you get .425 and ken had the bigger growth. plz rate me brainliest
Answer: Your answer will be A
Hope this helps
Step-by-step explanation:
Answer:
![\large\boxed{\dfrac{1}{x^2}+x^2=23}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cdfrac%7B1%7D%7Bx%5E2%7D%2Bx%5E2%3D23%7D)
Step-by-step explanation:
![\left(\dfrac{1}{x}+x\right)^2=25\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\\left(\dfrac{1}{x}\right)^2+2(x\!\!\!\!\diagup)\left(\dfrac{1}{x\!\!\!\!\diagup}\right)+x^2=25\\\\\dfrac{1}{x^2}+2+x^2=25\qquad\text{subtract 2 from both sides}\\\\\dfrac{1}{x^2}+x^2=23](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B1%7D%7Bx%7D%2Bx%5Cright%29%5E2%3D25%5Cqquad%5Ctext%7Buse%7D%5C%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5C%5C%5C%5C%5Cleft%28%5Cdfrac%7B1%7D%7Bx%7D%5Cright%29%5E2%2B2%28x%5C%21%5C%21%5C%21%5C%21%5Cdiagup%29%5Cleft%28%5Cdfrac%7B1%7D%7Bx%5C%21%5C%21%5C%21%5C%21%5Cdiagup%7D%5Cright%29%2Bx%5E2%3D25%5C%5C%5C%5C%5Cdfrac%7B1%7D%7Bx%5E2%7D%2B2%2Bx%5E2%3D25%5Cqquad%5Ctext%7Bsubtract%202%20from%20both%20sides%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7Bx%5E2%7D%2Bx%5E2%3D23)