Y = x^2 + 8x - 3
y = x^2 + 8x + (8/2)^2 - 3 - (8/2)^2
y = x^2 + 8x + 16 - 3 - 16
Answer:
a) Mean Time to failure (MTTF) = (10^7) hours
b) Availability of the system = 1
c) Mean Time to failure for 1000 processors = 10^4 hours.
Step-by-step explanation:
a) Failures in time (FIT) is traditionally reported as failure Per billion hours Of Operation.
1 billion = (10^9)
FIT = 100/(10^9) = 10^-7
MTTF = 1/FIT = 1/(10^-7) = (10^7) hours
b) Availability of the system = MTTF/(MTTF + MTTR)
MTTR = mean time to repair = 24hours
Availability of the system = (10^7)/((10^7) + 24) = 0.9999 = 1
c) FIT = 1000 (processors) × 100 (FIT per processor) = (10^5) per billion hours of operations = (10^5)/(10^9) = 10^-4
MTTF = 1/FIT = 1/(10^-4) = (10^4) hours
QED!!
Answer:
see explanation
Step-by-step explanation:
Given
V = πr²h ( isolate h by dividing both sides by πr² )
= h
When V = 36π , r = 3 , then
h = 
= 
= 4 cm
Answer:
Uche's pumping rate is <u>300 mL/s</u>.
Step-by-step explanation:
Given:
Uche pumps gasoline at a rate of 18 L/min.
Now, to find Uche's pumping rate in mL/s.
The rate at which Uche pumps gasoline = 18 L/min.
So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:
<u>1 L/min = 16.6667 mL/s.</u>
18 L/min = 16.6667 × 18 mL/s.
18L/min = 300 mL/s.
Therefore, Uche's pumping rate is 300 mL/s.
