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vlabodo [156]
3 years ago
14

Bill and Gwyll are going to the on holiday to the USA

Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0

Answer:

Bill

Step-by-step explanation:

1) we need to divide the dollars by the pounds to get the unit rate:

729/450=$1.62/1 pound(this is Bills exchange rate)

780/500= $1.56/1 pound(Gwens exchange rate)

1.62>1.56 so Bill has the better deal

hope this helps

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J'ai un problème de math que je n'arrive pas à résoudre:
irga5000 [103]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Pete works as a door to door vacuum salesman and earns a base salary of $400 per week plus 8% commission on
ololo11 [35]

Answer:

$516.48

Step-by-step explanation:

Base salary is what Pete will be paid whether he makes a sale or not.

Sales commission is the percentage of the value of the sale that Pete makes which is added to his base salary.

Base salary = $400

Total sales last week = $1456

Commission = 8% of total sales

Commission of last week = 8% of $1456

= 0.08*1456 = $116.48

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3 years ago
10 lbs to 6 lbs need percentage<br>please give step by step
bazaltina [42]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Tanzania [10]

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3 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
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