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Answer : The balanced chemical equation is,
Explanation :
Rules for the balanced chemical equation in basic solution are :
- First we have to write into the two half-reactions.
- Now balance the main atoms in the reaction.
- Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
- If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
- If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion
at that side where the less number of hydrogen are present. - Now balance the charge.
The half reactions in the basic solution are :
Reduction : 
......(1)
Oxidation : 
.......(2)
Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.
The balanced chemical equation in a basic solution will be,
СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃
<h3>Further explanation</h3>
Alkenes are unsaturated hydrocarbons that have a -C = C- double bond.
If there are 2 double bonds it is called an alkadiene, and if there are three double bonds it is called an alkatriene
General formula for Alkenes: CnH2n
addition reactions to alkenes follow Markovnikov's rule. in the addition reaction of hydrogen halide (HX), the halogen atom (X) will be bonded to the carbon atom that binds less H atom.
If the double-bonded carbon atom has the same number of H atoms attached to it, then the X atom will tend to be attached to the carbon atom with the longer alkyl group.
Addition reaction of propene compounds with HCl
СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃
CH - this carbon atom binds fewer H atoms, so Cl is bonded to this bond
Answer: hope this helps
To make molar NaCl solutions of other concentrations dilute the mass of salt to 1000ml of solution as follows:
0.1M NaCl solution requires 0.1 x 58.44 g of NaCl = 5.844g.
0.5M NaCl solution requires 0.5 x 58.44 g of NaCl = 29.22g.
2M NaCl solution requires 2.0 x 58.44 g of NaCl = 116.88g.
Explanation:
Answer: 0.83mol/m3
Explanation:
Number of mole = 2.5 mmol = 0.0025mol
Recall
1L = 0.001m3
Therefore 3L = 3x0.001 = 0.003m3
0.003m3 contains 0.0025mol
Therefore, 1m3 will contain = 0.0025/0.003 = 0.83mol
The concentration in mol/m3 is 0.83mol/m3
