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Inessa05 [86]
3 years ago
5

When a compound containing cesium ions is heated in a Bunsen burner flame, photons with an energy of 4.30 x 10-19 J are emitted.

What is the wavelength and color of the cesium flame?
Chemistry
1 answer:
inessss [21]3 years ago
6 0

<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.

<u>Explanation:</u>

To calculate the wavelength, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = Energy of 1 photon = 4.30\times 10^{-19}J

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Putting values in above equation, we get:

4.30\times 10^{-19}=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda }\\\\\lambda=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{4.30\times 10^{-19}}=4.62\times 10^{-7}m=462nm

The range of wavelength of blue light lies in range of 500 nm - 435 nm

The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm

Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.

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What is the Kelvin temperature of the air in a tire if the pressure inside the tire is 188 kPa at 32°C. While driving under peri
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Answer:

  • <u>414K</u>

Explanation:

The question is not completely clear because some missing parts or grammar (syntax) errors.

Interpreting it, the question is <em>what is the Kelvin temperatue of the air in a tire, when the pressure in the tire has increased to 225 kPa, if the initial conditions of the air inside the tire were 188kPa of pressure and a temperature of 32ºC.</em>

To solve this, you can assume constant volume and use the law of Gay-Lussac for ideal gases:

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        T_2=413.90K\approx 414K\longleftarrow answer

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3 years ago
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