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lora16 [44]
3 years ago
15

Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

2500

Step-by-step explanation:

Let the first square number be x^2 then the next square number is (x+1)^2.

The difference between these two consecutive numbers is 99.

This implies that:

(x+1)^2-x^2=99

We expand to get:

x^2+2x+1-x^2=99

Simplify:

2x=99-1

2x=98

Divide both sides by 2

x=49

Therefore the value of the larger perfect number is

(49+1)^2=50^2=2500.

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48.8m

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=> a = \sqrt{148.84} = 12.2

Formula for square perimeter = 4a = 4 x 12.2 = 48.8 m

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The answer is 86

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A researcher posed a null hypothesis that there was no significant difference between boys and girls on a standard memory test.
kompoz [17]

Complete Question

A researcher posed a null hypothesis that there was no significant difference between boys and girls on a standard memory test. He randomly sampled 40 girls and 40 boys in a community and gave them the standard memory test. The mean score for girls was 68 and the standard deviation of mean was 5.0. The mean score for boys was 66 and the standard deviation of mean was 5.0. What is the p-value and your conclusion at alpha 0.05

Answer:

The p-value is  p-value =0.073614

 The conclusion is  

There is sufficient evidence to support the claim  that there was no significant difference between boys and girls on a standard memory test

Step-by-step explanation:

From the question we are told that

      The sample size of boys and girls is  n_1= n_2 = n  = 40

      The standard deviation is  s_1=   s_2 = s = 5

        The level of significance is  \alpha = 0.05

       The sample mean for boys is  \= x_1 =66  

The null hypothesis is  H_o :  \mu_1 = \mu_2

The alternative hypothesis is  H_a :  \mu_1 <  \mu_2

 Generally the test statistics is mathematically represented as

           z = \frac{\= x_1 - \= x_2 }{ \sqrt{\frac{s_1 ^2 }{n_1}  + \frac{s_2 ^2 }{n_1}  } }

=>       z = \frac{66 -68 }{ \sqrt{\frac{5^2 }{40}  + \frac{5 ^2 }{40}  } }

=>       z = -1.789

From the z table  the area under the normal curve to the left corresponding to    -1,789   is

          P(Z <  -.1789 ) = 0.036807

Generally the p-value is mathematically represented as

         p-value =  2 P(Z <  -.1789 )

=>      p-value = 2 * 0.036807

=>      p-value =0.073614

From the values obtained we see that  p-value <  \alpha hence

The decision rule is  

Fail to reject the null hypothesis

 The conclusion is  

There is sufficient evidence to support the claim  that there was no significant difference between boys and girls on a standard memory test

 

3 0
3 years ago
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