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lora16 [44]
3 years ago
15

Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

2500

Step-by-step explanation:

Let the first square number be x^2 then the next square number is (x+1)^2.

The difference between these two consecutive numbers is 99.

This implies that:

(x+1)^2-x^2=99

We expand to get:

x^2+2x+1-x^2=99

Simplify:

2x=99-1

2x=98

Divide both sides by 2

x=49

Therefore the value of the larger perfect number is

(49+1)^2=50^2=2500.

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Simplify the following expression (3x^2y)^3
kolezko [41]

Answer:

\large\boxed{\left(3x^2y\right)^3=27x^6y^3}

Step-by-step explanation:

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3 years ago
What is the equation of the line that passes through the point<br> (5,-2) and has a slope of 6/5
LenKa [72]

Answer:

y = \frac{6x}{5} - 8

Step-by-step explanation:

given slope m = \frac{6}{5}

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y - y1 = m(x- x1)

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further you can multiply by 5 to get rid of fraction

5y = 6x - 40

5 0
2 years ago
QUESTION 3
eduard

Athe answer is -2  because it is behind the 0 and will be negative and it is two lines away from the 0 so the answer is -2

3 0
3 years ago
What are these slopes?
Nookie1986 [14]

Answer:

4. \frac{-5}{1} or -5 (It's a negative slope)

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4 0
2 years ago
PLEASE HELP ME!!! I WILL GIVE YOU BRAINLIEST
Kay [80]

Answer:

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5 0
2 years ago
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