Let c represents the cost of a candy apple and b represents the cost of a bag of peanuts.
Darius can purchase 3 candy apples and 4 bags of peanuts. So his total cost would be 3c + 4b. Darius can buy 3 candy apples and 4 bags of peanuts in $11.33,so we can write the equation as:
3c + 4b = 11.33 (1)
Darius can purchase 9 candy apples and 5 bags of peanuts. So his total cost would be 9c + 5b. Darius can buy 9 candy apples and 5 bags of peanuts in $23.56,so we can write the equation as:
9c + 5b = 23.56 (2)
<span>Darius decides to purchase 2 candy apples and 3 bags of peanuts. The total cost in this case will be 2c + 3b. To find this first we need to find the cost of each candy apple and bag of peanuts by solving the above two equations.
Multiplying equation 1 by three and subtracting equation 2 from it, we get:
3(3c + 4b) - (9c + 5b) = 3(11.33) - 23.56
9c + 12b - 9c - 5b = 10.43
7b = 10.43
b = $1.49
Using the value of b in equation 1, we get:
3c + 4(1.49) = 11.33
3c = 5.37
c = $ 1.79
Thus, cost of one candy apple is $1.79 and cost of one bag of peanuts is $1.49.
So, 2c + 3b = 2(1.79) + 3(1.49) = $ 8.05
Therefore, Darius can buy 2 candy apples and 3 bags of peanuts in $8.05</span>
S = (5g -4y)/9
hope this helps
The answer is forty four 44
Answer:
m = 35
Step-by-step explanation:
2m + m -15 = 90
3m -15 = 90
+15 +15
3m = 105
/3 /3
m = 35
To check the work just insert 35 for m:
2(35) + 35 -15 = 90
70 + 35 -15 = 90
105 - 15 = 90
90 = 90
Hey there! I'm happy to help!
There were 5 tests needed to make an average of 77. These numbers have to add up to 385 (77×5) because that is what you divide by 5 to find the average which is 77.
Now, we want to find an average of 80 with 6 numbers. We multiply 80 and 6, showing us that the sum of these 6 numbers must be 480. Since 5 of these numbers are the same as with the 77 average, we know that one test score (the one Brady needs to get) is added to 385 to give us 480.
480-385=95
Therefore, Brady needs to earn a 95% on the last test to receive a B in the class.
