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Shtirlitz [24]
3 years ago
6

What is the constant proportionality, in dollars per granola bar

Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

4 granola bars is $9.00    12 granola bars is $27.00     24 granola bars is $54.00

Step-by-step explanation:

You might be interested in
This is urgent I need help!
Nata [24]

Answer:

Step-by-step explanation:

1. Write an expression to show how to calculate the number of buses needed. Make sure to include parenthesis to show what should be done first since order of operations is important.

(9*25)+4+(2*4)=237 (total number of people going to the museum

Each bus,excluding the driver,holds 44 people

237/44 = 5.3863636363.......

2. How many buses will be needed?

 6 buses are needed

3. Why must the answer to the problem be a whole number?

Buses cannot be divided in fractions It should be or 5 buse or 6

But 5 buses are not enough

4. Why shouldn't you round the answer the usual way?

Even when rounded it is still a decimal and buses need to be counted by whole number

5. Can your answer be classified as a rational number? Explain why or why not.

6 is a rational number (whole number)

5.38636363.......is rational ( repeating decimal

8 0
3 years ago
What ordered pair is a solution of the equation 2x-y=9
ss7ja [257]

(0,−9),(1,x−9),(2,4x−9)

3 0
3 years ago
Read 2 more answers
5 roses cost $55. What will 4 roses cost?
kodGreya [7K]
Divide 55 by 5. get 11 times that by 4. you're welcome

3 0
3 years ago
Read 2 more answers
Solve for n. 2n +2 &gt; 16<br> A)n=7<br> B)n&lt;7<br> C)n&gt;7<br> D)n&lt;-7
Alex

Inequality : 2n + 2 > 16

2n > 16 - 2
2n > 14
n > 14/2
n > 7

-> Answer C

6 0
2 years ago
Read 2 more answers
Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
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