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3 years ago

Solve the equation 3(x-4)=2(x+6)

Mathematics

1 answer:

Daniel [21]3 years ago

5 0

Answer:

x=24

Step-by-step explanation:

When distributing using the distributive property, you get 3x- 12=2x+12. To solve for x, you need to isolate it. If you subtract 2x from both sides, you get x-12=12! All that’s left to do is add 12 to both sides, which gives you x=24.

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Can you please use my for gauth code GHD989

viva [34]

Answer:

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3 years ago

Find the volume of the solid generated when R (shaded region) is revolved about the given line. x=6−3sec y, x=6, y= π 3, and

Dmitrij [34]

Answer:

$V=9\pi\sqrt{3}$

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

$V=\int\limits^b_a {\pi r^{2}} \, dy$

where:

$r=6-(6-3 sec(y))$

$r=3 sec(y)$

a=0

$b=\frac{\pi}{3}$

so the volume becomes:

$V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy$

This can be simplified to:

$V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy$

and the integral can be rewritten like this:

$V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy$

which is a standard integral so we solve it to:

$V=9\pi[tan y]\limits^\frac{\pi}{3}_0$

so we get:

$V=9\pi[tan \frac{\pi}{3} - tan 0]$

which yields:

$V=9\pi\sqrt{3}$ ]

6 0

4 years ago

PLSSS ANSWER, 35 pointss

xxTIMURxx [149]

Answer:

$(y - 5)(x + y)$

${(x - y)}(x - y + a)$

$(b - 3)(5b - 17)$

Step-by-step explanation:

1. The given polynomial is

$x(y - 5) - y(5 - y)$

We need to factor the second part to get:

$x(y - 5) + y(y - 5)$

We factor y-5 to obtain:

$(y - 5)(x + y)$

2. We have

${(x - y)}^{2} - a(y - x)$

We again factor -1 from the second part to get:

${(x - y)}^{2} + a(x- y)$

We now factor x-y to get:

${(x - y)}^{2} + a(x- y)$

${(x - y)}(x - y + a)$

3. We have

$2(3 - b) + 5 {(b - 3})^{2}$

We factor negative 1 from the first part to get

$- 2(b - 3) + 5 {(b - 3})^{2}$

We now factor b-3 to get:

$(b - 3)( - 2 + 5(b - 3))$

We now simplify to get:

$(b - 3)( - 2 + 5b - 15) = (b - 3)(5b - 17)$

4 0

3 years ago

Hannah weighed 7.2 pounds at birth. Her weight was recorded at each of her infant doctor visits. The records from her appointmen

olchik [2.2K]

So If Hannah weighed 7.2 lb at birth during the six months that are shown on the table hanna puts on 8.7 during those six months so if we’re estimating what her weight will be at her one year visit

8.7(what she put on during the six months)+ 15.9 (her weight now)= 24.6

Answer: I estimate she will weigh 24.6lb at her one year visit

Hope this helps

5 0

3 years ago

What's the answer to these questions

siniylev [52]

19) 3/8
27) 14/15
23) 11/24

3 0

3 years ago