Answer:
Step-by-step explanation:
Length = 2W
P= 2L + 2W
60 = 2(2W) + 2W
60= 4W +2W
60 = 6W
60/6W = 6W/6W
w = 10
Length = 2(10)
Length = 20
P= 2L + 2W
60= 2(20) + 2(10)
60= 40 +20
60 = 60
Answer:
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Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
4 units wide would be the answer bc the deminsions of the legs wouldn't change for a rectangle or a triangle
