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Studentka2010 [4]
3 years ago
9

Explain how finding 4×30 he can help you find 4×5384 then find the both products

Mathematics
1 answer:
wlad13 [49]3 years ago
3 0
You can do this by doing 4 x 384, and you also want to find 4 x 5384 is then all you have to do is multiply the product of that by 5,000. Or to make life easier, do 5 times the product, and then add 3 zeros to the answer.
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Fill in the blank
Gnom [1K]

Answer:

<u>multiply</u> the base and <u>add </u>the exponents

4 0
3 years ago
You want to save for retirement. assuming you are now 25 years old and you want to retire at age 50, you have 25 years to watch
mr_godi [17]

Answer:

4250

Step-by-step explanation:

0.13 = 13%

1000×0.13=130
130×25= 3250 + 1000 = 4250

What I did:

You have to turn the percent to a decimal first

Then multiply the decimal by the first investment amount (1000)

then multiply that by the years that you have before retirement
You add that amount plus the 1000 you have started with

8 0
2 years ago
What the word form 485,830
Anastasy [175]

the word form of 485,830 is Four hundred eighty-five thousand eighty hundred thirty
7 0
3 years ago
Read 2 more answers
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
Find the value of X so that the function has the given value t(x)=3x; t (x)= 24
Fed [463]

Answer:

here is your answer....

Step-by-step explanation:

lets take x as 8

t(8)=3*8

t(8)=24

Therefore:

we get t(x)=24 from equation t(x)=3x

8 0
3 years ago
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