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pashok25 [27]
3 years ago
15

A machinist can produce 114 parts in 6 mins.At this rate,how many parts can the machinist produce in 15 mins

Mathematics
1 answer:
inysia [295]3 years ago
5 0
114\ parts\ in\ 6\ min\\\\
x\ parts\ in\ 15\ min\\\\
making\ proportion:\\
114-6\\
x-15\\\\cross\ multiplication\\\\
114*15=6x\\\\
1710=6x\ \ \ \ | divide\ by\ 6\\\\
x=285\\\\
285\ parts\ can\ be\ produced\ in\ 15min
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A random sample of 64 students at a university showed an average age of 20 years and a sample standard deviation of 4 years. The
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Answer:

The 90%  confidence level is  19.15<  L  <   20.85

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From the question we are told that

     The sample size is  n =  64

     The mean age is  \= x  =  20  \ years

      The standard deviation  is   \sigma  =  4 \ years

 

Generally  the degree of freedom for this data set is mathematically represented as

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substituting values

        df  = 64 -  1

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          \alpha  =  100 - 90

         \alpha  =10 %  

         \alpha   = 0.10

Now   \frac{\alpha }{2}  =  \frac{0.10}{2}  = 0.05

Since we are considering a on tail experiment

The  critical value for half of  this significance level at the calculated  degree of freedom is obtained from the critical value table as

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   The margin for error is mathematically represented as

          MOE  =  t_{df ,  \frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

substituting values  

          MOE  = 1.699  *   \frac{4 }{\sqrt{64} }

         MOE  = 0.85

he 90% confidence interval for the true average age of all students in the university is evaluated as follows

           \= x - MOE  <  L  <  \= x  + E

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         20  - 0. 85 <  L  <   20  + 0.85

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