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grandymaker [24]
3 years ago
9

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

t force acts upon an object with mass 8 kg, the acceleration of the object is 7 /ms2. If the same force acts upon another object whose mass is 28 kg, what is this object's acceleration?
Physics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer: The acceleration of 28 Kg object will be 2 m/s^{2}

Explanation: Force acting on an object is defined as mass times acceleration acting on it.

Mathematically it is defined as:

Force = mass \times acceleration

F = 8 \times 7 = 56 N

If the same force is acting on a 28 Kg object then the acceleration of the object will be equals to force to mass ratio.

Acceleration = \frac{Force}{Mass}  = \frac{56}{28} = 2 m/s^{2}

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the power of a physicians eyes is 57.1 D while examinging a patient. how far from her eyes (in m) is the feature being examined.
yanalaym [24]

Answer:

14 cm

Explanation:

Power of eye = 57.1 D

The relation between the focal length and the power is

f = 1 / P = 1 / 57.1 = 0.0175 m = 1.75 cm

The distance between the image and the lens is, v = 2 cm

Let the distance between the object and the eye is u

Use the lens equation

1/ f = 1 / v - 1 / u

1 / 1.75 = 1 / 2 - 1 / u

1 / u = 1 / 2 - 1 / 1.75

1 / u = (1.75 - 2) / 3.5

u = - 14 cm

Thus, the distance between the feature and eye is 14 cm .

8 0
3 years ago
A 6.0-kg ball is sliding to the right at 25.0m/s and strikes a second ball (15-kg) that is initially at rest head-on. After the
katrin [286]

Answer:

15 m/s to the right

Explanation:

Let's say right is positive and left is negative.

Momentum is conserved:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(6.0 kg) (25.0 m/s) + (15 kg) (0 m/s) = (6.0 kg) (-12.5 m/s) + (15 kg) v₂

v₂ = 15 m/s

5 0
3 years ago
is a 1.5 V battery is connected in a simple circuit to a lightbulb with a resistance of 8 Ohms the amount of current flowing thr
adoni [48]
.1875 Amperes. 
V=IR  1.5v=8Ω*I
I= .1875 A
6 0
3 years ago
The displacement of particle moving along on x axis is given by x = 18t + 5.0t^2, where x is in meters and t is in seconds Calcu
Masja [62]

Answer:

38 m/s

43 m/s

Explanation:

x = 18t + 5.0t²

The instantaneous velocity is the first derivative:

v = 18 + 10.t

At t = 2.0:

v = 18 + 10.(2.0)

v = 38 m/s

The average velocity is the change in position over change in time.

v = Δx / Δt

v = [ (18t₂ + 5.0t₂²) − (18t₁ + 5.0t₁²) ] / (t₂ − t₁)

Between t = 2.0 and t = 3.0:

v = [ (18(3.0) + 5.0(3.0)²) − (18(2.0) + 5.0(2.0)²) ] / (3.0 − 2.0)

v = [ (54 + 45) − (36 + 20.) ] / 1.0

v = 99 − 56

v = 43 m/s

6 0
3 years ago
How far is the sun away from earth
lisabon 2012 [21]

Answer:

The Sun is at an average distance of about 93,000,000 miles (150 million kilometers) away from Earth. It is so far away that light from the Sun, traveling at a speed of 186,000 miles (300,000 kilometers) per second, takes about 8 minutes to reach us.

Explanation:

8 0
3 years ago
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