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sesenic [268]
4 years ago
13

When a sound source is moving away from an observer, the observer will hear a lower pitch. This is due to

Physics
2 answers:
Art [367]4 years ago
6 0

a decrease in the frequency of the sound wave.

Explanation:

When a sound source is moving away from an observer, the observer will hear a lower pitch due to a decrease in the frequency of the sound wave. This is known as the Doppler's effect.

  • As the sound source moves closer to the observer, they hear a higher pitch in the reverse process.
  • A sound wave transmits vibrational energy from the source to the hearer.
  • A  sound wave has frequency, amplitude, velocity and wavelength just like other wave types.
  • The frequency of a wave is the number of waves that passes through a point at a time.
  • This is related to the the wavelength of a wave.
  • Waves of a high frequency are known to have short wavelengths and vice versa.
  • To hear a low pitch, the source moves away and the wavelength between successive crests and troughs on a wave increases considerably.

Learn more:

Sound waves brainly.com/question/2845448

#learnwithBrainly

shepuryov [24]4 years ago
5 0

Answer:

its the last one

Explanation:

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Sati [7]

Answer:

m_2 = 23 kg

Explanation:

As we know that the tension in two strings are

T_2 = 111 N

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F_{net} = ma

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(m_1 + m_2)a = T_2

(12 + m_2)a = 111

also we have

(m_1 + m_2 + m_3 + m_4) a = T_4

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now divide two equations

\frac{222}{111} = \frac{47 + m_2}{12 + m_2}

2m_2 + 24 = 47 + m_2

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7 0
4 years ago
A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.
Jobisdone [24]

Answer:

F=507.7N

Explanation:

According to Newton's second law:

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\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.

F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N

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You are driving at 25 m/s with your cruise control on when you see a fallen tree in the road. It takes you 0.30 s to put on the
xxTIMURxx [149]

Explanation:

Given data

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s= 25*0.3s

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Also the rate of decrease in aceleration is 5m/s^2

we can also calculate the distance covered at this rate

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s= 62.5m

The total  distance covered between putting on the brakes and decelareation is  7.5+62.5= 70m

Given that the tree is 75m ahead, the car would not hit the tree

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