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forsale [732]
3 years ago
5

Just one help please

Mathematics
1 answer:
Helga [31]3 years ago
6 0
<em><u>Hello</u></em>
<em><u>A is correct</u></em>
<em><u>B is correct</u></em>
<em><u>C is correct
Good luck!
</u></em>
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answer: you would just substitute all of the values you see for b into the equation where there's a b

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3 years ago
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Identify any extrema of the function by recognizing its given form or its form after completing the square. Verify your results
Andrews [41]

Answer:

Step-by-step explanation:

Given that,

g(x, y) = 5 - (x - 3)² - (y + 2)²

Let find the grad of the function,

The grad of a function is defined as

∇g= ∂g/∂x •i + ∂g/∂y •j + ∂g/∂z •k

∇g = gx•i + gy•j + gz•k

gx = -2(x-3) = -2x+6

gy = -2(y+2) = -2y -4

∇g = (-2x+6) •i + (-2y-4)•j

We have a maximum or a minimum If g conservative, then, ∇g = 0i +0j

Then comparing this to the grad of the function

(-2x+6) •i + (-2y-4)•j = 0i +0j

Then, -2x+6 = 0

2x=6

x = 3

Also, -2y-4=0

-2y=4

y = -2

Then, g(x, y) = 5 - (x - 3)² - (y + 2)²

g(x, y) = 5 - (3 - 3)² - (-2 + 2)²

g(x, y) = 5

So the critical point is (3, -2, 5)

gx =-2x+6

Second derivative of gx with respect to x

gxx=-2

gy=-2y-4

Second derivative of gy with respect to y

gyy=-2

Second derivative of gx with respect to y

gxy =0

d =gxxgyy - (gxy)²

Then, gyy=gxx

d = -2×-2 -0²

d = 4-0=4

Since d>0

Since d is greater than 0, then, it is not a chair points.

Then, since gxx=-2<0, gyy=-2<0

Cause the second derivative in x (or in y) is less than zero, then the point is relatively maximum

So the maximum point is (3, -2, 5).

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3 years ago
Doug's teacher told him that the standardized score (z-score) for his mathematics
BigorU [14]

Answer:

Doug’s test score is 1.20 standard deviations above the average test score of the students in the course.

I just took the test and got it right :)

Step-by-step explanation:

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2 years ago
Solve equation for y: -4x+8y=24
Nesterboy [21]
-4x +8y = 24

8y = 24+ 4x
y = 24/8 + 4x/8
y = 3+ x/2

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#MissionExam001
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Someone please help me with this geometry proof question ASAP!
vivado [14]

Answer:

if ∠Q=∠R

draw an angular bisector from P to QR in which it intersect wit Qr at point S

now we have two triangle : QPS and RSP

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