With u = <-7, 6> and v = <-4, 17>, we have
u + 3v = <-7, 6> + 3 <-4, 17> = <-7, 6> + <-12, 51> = <-19, 57>
We want to find a vector w such that
u + 3v + w = <1, 0>
Subtract u + 3v from both sides to get
w = <1, 0> - (u + 3v) = <1, 0> - <-19, 57>
w = <20, -57>
Answer:
(-∞, -4] ∪ [5, ∞)
Step-by-step explanation:
Hi!
Alright, so greater (or less) than or equal to is denoted with a bracket.
If x is less than or equal to -4, then the bracket is on the left side.
(___, -4]
Because x is <em>any</em> number under or equal to -4, x can range from negative infinity. However, we use a parentheses for infinity because infinity can never truly be reached.
So, x 
-4 = (-∞, -4]
X
5
Equal to = bracket
X is any number above 5, so
[5, ∞)
Because we want both of these, we use the union sign (∪)
so,
= (-∞, -4] ∪ [5, ∞)
Answer:
y = 4/3x + 1.
Step-by-step explanation:
The equation of the lines passing through (2,1) and (6,7) is:
y - 7 = (7-1)/(6- -2)(x - 6)
y - 7 = 6/8(x - 6)
y = 3/4(x - 6) + 7
y = 3/4x + 5/2.
So the line perpendicular to it has slope -1/3/4 = -4/3:
y - 9 = -4/3(x + 6)
y = -4/3 x - 8 + 9
y = 4/3x + 1.
Answer:
20
Step-by-step explanation:
We already have our first value 3.4 and the second value 17. Let's assume the unknown value is Y which answer we will find out.
As we have all the required values we need, Now we can put them in a simple mathematical formula as below:
Step 1 ---> 3.4 = 17% × Y
Step 2 ---> 3.4 = 17/100 × Y
Multiplying both sides by 100 and dividing both sides of the equation by 17 we will arrive at:
Step 3 ---> Y = 3.4 × 100/17
Step 4 ---> Y = 3.4 × 100 ÷ 17
Step 5 ---> Y = 20
Finally, we have found the value of Y which is 20 and that is our answer.
<h3><u>
*You can easily calculate 3.4 is 17 percent of what number by using any regular calculator, simply enter 3.4 × 100 ÷ 17 and you will get your answer which is 20*</u></h3>
Answer:
In statistics, the 68–95–99.7 rule, also known as the empirical rule, is a shorthand used to remember the percentage of values that lie within a band around the mean in a normal distribution with a width of two, four and six standard deviations, respectively; more accurately, 68.27%, 95.45% and 99.73% of the values lie ...
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