Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
Answer:
C. The decimal terminates after 2 decimal places.
Step-by-step explanation:
If we move twice to the right, we will see that it will now see 1.14. I will send you a picture.
hope this helps.
Answer:
105
Step-by-step explanation:
since its a straight line it would add up to 180 degrees so 52 + 23 + 75 and you need 180 so 180-75 which gives 105 which is the missing angle
A is correct.
-8, -4, 0, 2
-|-4| becomes -(4) which becomes -4.
The answer would be
A. 3/4
