The quadratic term is 2x^2.
Begin
3x-4=14
3x=18
x=6
.5n=1.25
n=2.5
x+1=2x-2
x+3=2x
3=x
x+3=10
x=7
6x-13=-11
6x=2
x=1/3
p=4-p
2p=4
p=2
End
Answer:
36,000 possible codes.
Step-by-step explanation:
I guess you want the total number of arrangements possible.
The first digit can be any number from 0 to 8. the middle numbers must each be any number from 0 to 9 and the last digit must be 2,4,6 or 8.
So the number of arrangements possible = 9 * 10 * 10 * 10 * 4
= 36,000.
5 (7 + 23)
(Use distributive property to solve)
1. 5*7 + 5*23
2. 35 + 115
3. 150
