You just have to figure it where you can place 2 solid lines and get 10 triangles ( i can only get 9). Think about the pentagon in the middle of the triangles and see if somehow you can create more triangles using only the two straight lines.

6 0

2 years ago

Solve:

STatiana [176]

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

The given equation is:

$3-k=\sqrt{3k+1}$

Square both sides of the equation

$(3-k)^2=3k+1$

Expand the left side of the equation above

$(3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1$

Write the quadratic equation in standard form

$k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\$

Factor the quadratic equation

$(k-8)(k-1)=0$

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

Learn more here: brainly.com/question/25840704

8 0

2 years ago

Read 2 more answers

the number of boys who solved a tough math problem is the same as the number of girls who did not solve it. Are there more girls

Harrizon [31]

Answer:

I want to say the answer is No, I'm sorry if I am wrong.

6 0

2 years ago