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n200080 [17]
2 years ago
15

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER. What is the volume

of the square pyramid?
V=___cm^3
(Round to the nearest tenth as needed)

Mathematics
1 answer:
GarryVolchara [31]2 years ago
4 0

Answer:

114.3cm^3

Step-by-step explanation:

Square Pyramid Formulas derived in terms of side length a and height h: Volume of a square pyramid

V = (1/3)(Base area of a square)(Height of the square pyramid).

V = (1/3)area^{2}hight

Area of the square

A = 7 x 7

A = 49

V = (1/3)49 x 7

V = (1/3)343

V = 114.(a repeating term)3

since we rounded

V = 114.3cm^3

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A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of
Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

<em><u>Solution: </u></em>

Given:

Height of the cylindrical tent = h = 3.3 m

Diameter of it's base = d = 100m

radius = \frac{diameter}{2} = \frac{100}{2} = 50

r = 50 m

<em><u>Curved surface area of cylinder:</u></em>

C.S.A = 2 \pi rh

C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2

Thus Curved surface area of cylinder = 1036.2 square meter

<em><u>Curved surface area of cone:</u></em>

C.S.A = \pi rl

C.S.A = 3.14 \times 50 \times 56.4 = 8854.8

Thus Curved surface area of cone = 8854.8 square meter

<em><u>Total curved area of tent:</u></em>

⇒ curved area of cone + curved area of cylinder

\rightarrow 8854.8 + 1036.2=9891

Thus total curved area of tent = 9891 square meter

<em><u>find total cost of canvas required in making the tent:</u></em>

The cost of canvas is 8 rupees per square meter

\rightarrow \text{total cost } = 9891 \times 8 = 79128

Thus total cost of canvas required in making the tent is rupees 79128

7 0
3 years ago
The endpoints of are A(2, 2) and B(3, 8). is dilated by a scale factor of 3.5 with the origin as the center of dilation to give
goldfiish [28.3K]

Answer:

The given line segment whose end points are A(2,2) and B(3,8).

Distance AB is given by distance formula , which is

if we have to find distance between two points (a,b) and (p,q) is

=  \sqrt{(p-a)^2+(q-b)^2}

AB= \sqrt{(3-2)^2+(8-2)^2}=\sqrt{1+36}=\sqrt{37} = 6.08 (approx)

Line segment AB is dilated by a factor of 3.5 to get New line segment CD.

Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)

Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)

CD = AB × 3.5

CD = √37× 3.5

     = 6.08 × 3.5

= 21.28 unit(approx)

2. Slope of line joining two points (p,q) and (a,b) is given by

m=\frac{q-b}{p-a}

m= \frac{8-2}{3-2}=6

As the two lines are coincident , so their slopes are equal.

Slope of line AB=Slope of line CD = 6




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4 years ago
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Answer:

proportion used: 7/20

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