Question

Solve for X, (with steps please) 0.46=0.527-[0.0562/2 * log(0.1+x/1.5-x)]

Answer 1

Rearrange the equation: 

$\frac{0.0562}{2} * log( \frac{0.1+x}{1.5 - x}) = 0.527 - 0.46 = 0.067$

Isolate the log on its own

$log (\frac{0.1 + x}{1.5 - x}) = \frac{0.067*2}{0.0562} = 2.42 (2dp)$

To get rid of the log you must do 10^2.42 

$\frac{0.1 +x}{1.5-x} = 10^{2.42} = 242.29 (2dp)$

Then multiply both sides by (1.5 - x)

$0.1 +x = 242.29(1.5-x)$

$0.1 + x = 363.44 - 242.29x$

Solve normally

$243.29x = 363.34 x = 363.34/243.29 x= 1.49344 x= 1.49 (2dp)$

Hope that helps. Please send me a message if there's patchy bits. Also I'm sure you'll figure this out, but just in case, anywhere I've put down a 2dp shows that I've rounded the number to 2 decimal places. It becomes a pain to deal with otherwise.