Answer:
the order is Paco, Tim, Jenny, Maria
Step-by-step explanation:
First compute the perimeter of the pool:
(21+33)*2=108 foot.
Since the material cover 232 ft^2, then it is sufficient to divide the above number over the length of the border like this:
232/108=2.1
The trip can be 2.1 ft in wide.
Answer:
27.5 mm
Step-by-step explanation:
The game piece has the shape of two identical square pyramids attached at their bases. Given that the perimeters of the square bases are 80 millimeters, and the slant height of each pyramid is 17 millimeters.
Let the side length of each of the side of the base of the pyramid be b, hence:
perimeter = 4b
80 = 4b
b = 20 mm. half of the side length = b/2 = 20 / 2 = 10 mm
The slant height (l) = 17 mm, Let h be the height of one of the pyramid, hence, using Pythagoras theorem:
(b/2)² + h² = l²
17² = 10² + h²
h² = 17² - 10² = 189
h = √189
h = 13.75 mm
The length of the game piece = 2 * h = 2 * 13.75 = 27.5 mm.
the solution is here,
the coordinate of centre of circle A is (3,2)
and the coordinate of centre of circle B is (3,0).
so the translation point from A to B is (3-0,0-2)=(3,-2).
Now the translation rule is given by (x+h,y+k)
where h is the tranalation anlong the x-axis and k is the translation along the y-axis.
For this problem, translation ruleis (x+3,y-2).
Then, radius of circle A(r1)=2 units
radius of circle B (r2)= 3 units
as the circle A is translated to B, the scale factor is
r2/r1=3/2=1.5
In conclusion, the translation rule for given circles is (x+3,y-2) and its scale factor is 1.5
