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Archy [21]
3 years ago
9

An online furniture store sells chairs for $100 each and tables for $550 each. Every day, the store can ship at most 25 pieces o

f furniture and must sell no less than $7000 worth of chairs and tables. If 9 chairs were sold, determine all possible values for the number of tables that the store must sell in order to meet the requirements. Your answer should be a comma separated list of values. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

(10, 11, 12, 13, 14, 15, 16)

Step-by-step explanation:

The minimum number of tables that the store has to sell in order to meet the requirements is given by:

(25-t)*100+t*550=7,000\\(550-100)t=7,000-2,500\\t = 10\ tables

The company must sell at least 10 tables.

Since the company already sold 9 chairs, and they can ship at most 25 items, they can sell at most 16 tables. Every integer number between the minimum and maximum is also possible:

(10, 11, 12, 13, 14, 15, 16).

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We need a system of equations here, one equation based on the NUMBER of tickets sold and another based on the MONEY earned by the sales.  We have 2 different types of tickets:  full price (f) and discount (d).  The total number of tickets sold is 428; therefore, the first equation is f + d = 428.  That accounts for the number of tickets sold.  Each full price is 10.25 which can be represented as 10.25f, and each discount ticket costs 8 which can be represented as 8d.  The money earned by selling these tickets at those prices was 3946.  That means that the second equation is 10.25f + 8d = 3946.  We will solve the first bolded equation for f to get f = 428 - d.  Sub that value in for f in the second bolded equation:  10.25(428-d) + 8d = 3946.  Distribute to get 4387 - 10.25d + 8d = 3946.  Combine like terms to get -2.25d = -441.  Solving for d we get 196.  That means that there were 196 discounted tickets sold.  Put that in for d in the first bolded equation to find the number of full price tickets.  f + 196 = 428,  and f = 232.  There were 232 full price tickets sold.  There you go!
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