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3 years ago

15

2 tenths is equal to____ fifths

2 answers:

Sunny_sXe [5.5K]3 years ago

5 0

To solve this, it is easiest to set up a proportion, letting x represent the number that we don't know.

2/10 = x/5

Now, we can use cross products to simplify this proportion. Cross products sets the products of the numerator and denominator of separate fractions equal to one another. It results in the equation:

(5)(2) = (10)(x)

Let's multiply out these numbers to further simplify the equation.

10 = 10x

Finally, we have to divide both sides by 10, to get our variable x alone

x = 1

Therefore, 2 tenths is equal to 1 fifth.

AveGali [126]3 years ago

3 0

Its 4 because if you draw a pie and give it 5 pieces and cut all those pieses in half. then color in 2 more pieses which is 4

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A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

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Read 2 more answers

Someone answer all 1-10 please

jarptica [38.1K]

1. -3/2
2. 2
3. 1/2
4.0
5. 1/2
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7. -1/4
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