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juin [17]
4 years ago
8

The midpoint of AB is M(7,-2). If the coordinates of A are (8,3), what are the coordinates of B?

Mathematics
1 answer:
strojnjashka [21]4 years ago
4 0

Answer:

Step-by-step explanation:

We can find it like:

x_{B}=  2x_{M}- x_{A} = 2*7 - 8 = 14 - 8= 6\\  \\y_{B}=  2y_{M}- y_{A} = 2*(-2) - 3 = - 4 - 3= - 7

The answer is B(6,-7).

Hope you understand.

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Reduce the following fraction: -32abc/64a^2bc^2
mafiozo [28]

Answer:

-\dfrac{1}{2ac}

Step-by-step explanation:

Given:

\dfrac{-32abc}{64a^2bc^2}

Reduce this fraction.

Work with numbers and different letters separately:

1. Numbers:

\dfrac{-32}{64}=-\dfrac{32}{32\cdot 2}=-\dfrac{1}{2}

2. Letter a:

\dfrac{a}{a^2}=\dfrac{a}{a\cdot a}=\dfrac{1}{a}

3. Letter b:

\dfrac{b}b}=1

4. Letter c:

\dfrac{c}{c^2}=\dfrac{c}{c\cdot c}=\dfrac{1}{c}

Hence,

\dfrac{-32abc}{64a^2bc^2}=-\dfrac{1}{2}\cdot \dfrac{1}{a}\cdot \dfrac{1}{c}=-\dfrac{1}{2ac}

5 0
4 years ago
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Is 94.84 an integer in math
aksik [14]

Answer:

No, an Integer is a whole number. Meaning no fractions or decimals

Step-by-step explanation:

6 0
3 years ago
Help meeee please!!!!!
ladessa [460]

Answer:

Step 3: Choice D

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Step 8: Choice C

(I saw in the top left corner of the picture that this is for Algebra II. I am in 8th grade, currently taking geometry, and I haven't taken Algebra II yet, but I <em>did</em> take Algebra I last year. I am 95% sure this is correct but if it isn't, the I sincerely apologize.)

7 0
3 years ago
Bailey was practicing karate and kicked the target 6 out of 20 times. Express the number of times she kicked the target as a fra
sattari [20]

Answer:

ok so here we know that Baily kicked the target 6 times out of 20 that  is 6/20 and then you just reduce the fraction dividing it by 2 so it will be  3/10

Step-by-step explanation:

hope it helps :)

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Chuge%20%5Cmathcal%5Ccolor%7Borange%7D%5Cboxed%7B%5Ccolorbox%7Bpurple%7D%7BQuestion%7D%7D" i
andrew-mc [135]

Answer:

let us consider a positive integer a

divided the positive integer a by 3, and let r be the remainder and B be the quotient and such that.

<h3>a=3b+r.........(1)</h3>

where =0,1,2,3

case 1:consider r=0

equation (1)becomes

<h3 /><h3>a=3b</h3>

on squaring both the side

  • a²=(3b) ²

  • a²=9b²

  • a²=3 x 3b²

<h3>a²=3m</h3>
  • where m=3b²
  • case 2: Let R=1

  • equation (1) become

<h3>a=3b+1</h3>

  • squaring on both the side we get

  • a²=(3b+1)²
  • a²=(3b) ²+1+2x(3b)x1
  • a²=9b²+6b+1
  • a²=3(3b²+2b) +1
<h3 /><h3>a²=3m+1</h3>

  • where m=3b²+2b
  • case3:let r=2
  • equation (1)becomes
<h3>a=3b+2</h3>
  • squaring on both the sides we get
  • a²(3b+2)²
  • a²=9b²+4(12x3bx2
  • a²9b²+(12b+3+1)
  • a²3(3b²+4b+1)+1
<h3 /><h3>a²3m+1</h3>

where m=3b²+4b+1

: square of any positive integer is of the form 3M or 3M + 1

: hence proved.

3 0
3 years ago
Read 2 more answers
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