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2 years ago

What is the answer to all

Mathematics

2 answers:

Burka [1]2 years ago

6 0

11.B. 21+g
12.B.1 because 5/1/5=1
13. 1.35 because 4-2.65=1.35
14. A. x>-1

Bingel [31]2 years ago

4 0

11. 21g
12. ?
13. X=1.35
14. X>-1

(I'm not sure about 12 because I don't have any paper to solve it at the moment. Sorry! Hope this helps anyway!)

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10 to the power of 3 times what equals 630

vekshin1

10³ · x = 630
x = ?

10³ = 10 × 10 × 10 = 1,000

630 ÷ 1000 = x
630 ÷ 1000 = 0.63
x = 0.63

So we have:

10³ · 0.63 = 630

6 0

3 years ago

Read 2 more answers

I’m new to this app so I don’t know how to give more points but I would appreciate it if you could help

faust18 [17]

Hi! The answer would be all real numbers!

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8 0

2 years ago

What is the value of b?<br><br> 0.4(3b+10)=19

Sergio039 [100]

Answer:

12.5

Step-by-step explanation:

Step 1:

0.4 ( 3b + 10 ) = 19 Equation

Step 2:

1.2b + 4 = 19 Multiply

Step 3:

1.2b = 15 Subtract 4 on both sides

Step 4:

15 ÷ 1.2 Divide

Answer:

b = 12.5

Hope This Helps :)

7 0

2 years ago

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

4 0

2 years ago

A rectangular garage is 15 yards long and 5 yards wide. It costs $2.00 per square yard to put in a new concrete floor. How much

pantera1 [17]

Say you have a box and theres one fifteen on two sides and one five on the other two side 15+15=30 and 5+5=10 and 30+10=40 and 40x2=80
Answer:$80

4 0

2 years ago