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Scilla [17]
3 years ago
9

If 4x+y= x solve for x.

Mathematics
1 answer:
erik [133]3 years ago
6 0

4x+y= x

Move all x term to left side

4x-x+y=0

Subtract 4x from 3x

3x+y=0

Move y term to right side

3x= -y

Divide both sides by 3

X= -y/3



Ok so if it's


4x+y= z solve for x


Move y to right side


4x= -y +z


Now divide both by 4 to get x alone


X= -y/4 + z/4

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pentagon [3]
First, multiply the first equation by 2.

That turns the first equation into:

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That way it can easily be added to the second equation:

6x - 2y = 16
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7x = 21
==========

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Now the equations can be solved easily:

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Insert x=3 in the original equation:

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5 0
3 years ago
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katovenus [111]

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  1 < x < 4 . . . . {x | x < 4 <u>and</u> x > 1}

Step-by-step explanation:

We want to write the answer as a compound inequality, if possible. As it is written, we can solve each separately.

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__

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So, the solution is ...

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As a compound inequality, this is written ...

  1 < x < 4

_____

<em>Comment on the problem</em>

The two answer choices shown don't make any sense. You might want to have your teacher demonstrate the solution to this problem.

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Answer:


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......what's the question?

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3 years ago
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