Answer:
I₂ = 25.4 W
Explanation:
Polarization problems can be solved with the malus law
I = I₀ cos² θ
Let's apply this formula to find the intendant intensity (Gone)
Second and third polarizer, at an angle between them is
θ₂ = 68.0-22.2 = 45.8º
I = I₂ cos² θ₂
I₂ = I / cos₂ θ₂
I₂ = 75.5 / cos² 45.8
I₂ = 155.3 W
We repeat for First and second polarizer
I₂ = I₁ cos² θ₁
I₁ = I₂ / cos² θ₁
I₁ = 155.3 / cos² 22.2
I₁ = 181.2 W
Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized
I₁ = I₀ / 2
I₀ = 2 I₁
I₀ = 2 181.2
I₀ = 362.4 W
Now we remove the second polarizer the intensity that reaches the third polarizer is
I₁ = 181.2 W
The intensity at the exit is
I₂ = I₁ cos² θ₂
I₂ = 181.2 cos² 68.0
I₂ = 25.4 W
(a) Intensity obeys inverse square law from basis of light passing through a given surface.
(b) Gravitation obeys inverse square law from the basis of force between two masses.
(c) The maximum magnitude of the acceleration of the block is 126.75 m/s².
<h3>
What is intensity?</h3>
Intensity is the ratio is ratio of power to area of a given surface.
I = P/A (W/m²)
where;
<h3>Universal gravitation law</h3>

Intensity and gravitation do not obey inverse square law for same reason;
- Intensity obeys inverse square law from basis of light passing through a given surface.
- Gravitation obeys inverse square law from the basis of force between two masses.
<h3>Acceleration of the block</h3>
a = v²/A
a = (3.9²)/0.12
a = 126.75 m/s²
Learn more about acceleration here: brainly.com/question/605631
#SPJ1
Answer:
Explanation:
Given
Work required 
Work done to eject the sodium ion from interior of the cell is given by the product of charge and Potential difference between inner and outer surface of the cell.

Charge on sodium ion 

Answer: [B]: The letter, "<em /> I " ; for current; in units of "Amps" .
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Centrioles are found in eukaryotic cells!