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Mrac [35]
3 years ago
7

Please need help with this

Physics
1 answer:
NeTakaya3 years ago
7 0

<u>Note that</u>:

The gravitational potential energy = mgh

where m: is the mass, g: the acceleration due to the gravity and h is the height from the earth surface

Then, we can increase the gravitational potential energy by increasing the mass or the height from the earth surface

<u>In our question</u>, we can increase the gravitational potential energy by

<u>A) Strap a boulder to the car so that it wights more.</u>

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The total charge a battery can supply is rated in mA⋅hmA⋅h, the product of the current (in mA) and the time (in h) that the batt
Nat2105 [25]

Answer:

118800 seconds

Explanation:

Given :

Voltage, V = 1.2 V

Resistance, R = 22 Ω

Applying Ohm's law, we get

Voltage, V = IR

Current $I=\frac{V}{R}$

           $I=\frac{1.2}{22}$

          I = 0.0545 A

Rate = 1800 mAh

Time taken, $t=\frac{1800 \times 10^{-3}}{0.0545}$

                       = 33 hr

                      = 118800 s

8 0
3 years ago
Virginia beach is 15 kilometers wide and 50 kilometers long. if 2 cm of rain falls on virginia beach, how many cubic meters of r
icang [17]
Assume that the shape of Virginia beach is rectangular.

Note that
1 km = 10³ m
1 cm = 10⁻² m

The area is
A = (15 km)*(50 km)
   = (15 x 10³ m)*(50 x 10³ m)
   = 7.5 x 10⁸ m²

Because 2 cm of rain fell, the volume is
V = (7.5 x 10⁸ m)*(2 x 10⁻² m) = 1.5 x 10⁶ m³

Answer:  1.5 x 10⁶ m³
4 0
3 years ago
If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical
erastovalidia [21]

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

<h3>Time of motion of the girl</h3>

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

  • v is initial vertical velocity = 0
  • t is time of motion
  • g is acceleration due to gravity

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

<h3>Final vertical velocity of the skydiver</h3>

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

Learn more about vertical velocity here: brainly.com/question/24949996

#SPJ1

4 0
2 years ago
5. The analytical method of adding vectors expressed in terms of their components may be applied to vectors in three dimensions,
Gwar [14]

Answer:

C = 17 i^ - 7 j^ + 16 k^ ,   | C| = 24.37

Explanation:

To work the vactor component method, we add the sum in each axis

C = A + B = (Aₓ + Bₓ) i ^ + (A_{y} + B_{y}) i ^ + (A_{z} + B_{z}) k ^

Cₓ = 12+ 5 = 17

C_{y} = -37 +30 = -7

C_{z} = 58 -42 = 16

Resulting vector

C = 17 i ^ - 7j ^ + 16k ^

The mangitude of the vector is

| C | = √ c²

| C | = √( 17² + 7² + 16²)

| C| = 24.37

6 0
3 years ago
A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult
Dvinal [7]

Answer:

Explanation:

Given

time taken t=2\ s

Speed acquired in 2 sec v=42\ m/s

Here initial velocity is zero u=0

acceleration is the rate of change of velocity in a given time

a=\frac{v-u}{t}

a=\frac{42-0}{2}=21\ m/s^2

Distance travel in this time

s=ut+0.5at^2

where  

s=displacement

u=initial velocity

a=acceleration

t=time

s=0+\0.5\times 21\times (2)^2

s=42\ m

so Jet Plane travels a distance of 42 m in 2 s                                

5 0
3 years ago
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