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3 years ago

The particles ejected from the sun during a coronal mass ejection is called

Physics

1 answer:

ipn [44]3 years ago

7 0

Answer:

Plasma

Explanation:

A Coronal Mass Ejection (CME) is an outburst of energy that occurs near the outer part of the sun's atmosphere which causes a production of plasma along with a magnetic field.

The outermost part of the sun's atmosphere is called the Solar Corona Although difficult to see, the corona can be seen during a total solar eclipse.

Plasma from CME are clouds of magnetized electrically charged particles which the solar wind causes to travel at a speed of 1.6 million km/hr.

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The line of action of the force \vec{F}=5\vec{i}-10\vec{j} F =5 i −10 j N passes through the point with coordinates (in meters

Morgarella [4.7K]

Answer:

$\tau = - 30 \hat k$

Explanation:

Position vector of the point of application of point of application of force is given as

$\vec r = 2\hat i + 2\hat j$

now we have have force

$\vec F = 5 \hat i - 10\hat j$

now the moment of force is given as

$\tau = \vec r \times \vec F$

$\tau = (2\hat i + 2\hat j) \times (5\hat i - 10\hat j)$

$\tau = -20\hat k - 10 \hat k$

$\tau = - 30 \hat k$

5 0

3 years ago

Compare the densities of two objects that have the same volume, but one feels heavier than the other.

motikmotik

We know, density = Mass / Volume
It represents density is directly proportional to mass and indirectly proportional to volume. So, at a constant volume, object with larger density will appear more heavier than that of object with smaller density.

In short, Heavier object will have the higher density than the other.

Hope this helps!

8 0

4 years ago

Determine the amount of time for polonium-210 to decay to one fourth its original quantity. The half-life of polonium-210 is 138

ira [324]

Answer: 276 days

Explanation:

This problem can be solved using the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=\frac{1}{4}A_{o}$ is the final amount of the material

$A_{o}$ is the initial amount of the material

$t$ is the time elapsed

$h=138 days$ is the half life of polonium-210

Knowing this, let's substitute the values and find $t$ from (1):

$\frac{1}{4}A_{o}=A_{o}2^{\frac{-t}{138 days}}$ (2)

$\frac{A_{o}}{4A_{o}}=2^{\frac{-t}{138 days}}$ (3)

$\frac{1}{4}=2^{\frac{-t}{138 days}}$ (4)

Applying natural logarithm in both sides:

$ln(\frac{1}{4})=ln(2^{\frac{-t}{138 days}})$ (5)

$-1.386=-\frac{t}{138days}ln(2)$ (6)

Clearing $t$ :

$t=276days$ (7)

7 0

3 years ago

What advantage does absolute-age dating have over relative-age dating? Explain

kramer

Relative age is the age of a rock layer (or the fossils it contains) compared to other layers. It can be determined by looking at the position of rock layers. Absolute age is the numeric age of a layer of rocks or fossils. Absolute age can be determined by using radiometric dating.

8 0

3 years ago

Name three things that are NOT made of matter

Stells [14]

Answer:

Light.

Sound.

Heat.

Energy.

Gravity.

Explanation:

5 0

3 years ago