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d1i1m1o1n [39]
3 years ago
7

Please Help me on this Question

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0
The internet always has the answers to books.... lol idk, i am stupid
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Does the following represent a Direct or Indirect variation? y = 5 Direct Indirect​
Nataly_w [17]

Answer:

Yes, y=5x is a direct variation and the constant of variation is 5 .

7 0
3 years ago
Read 2 more answers
Please help me with #1. I need an equation and the number of years.
weeeeeb [17]
1. 12000(1 - n/5) = 2,400
     12000 - 2400n = 2400
      - 2400n + 12000 - 12000 = 2400 - 12000
      - 2400 = - 9600
             n = 4, After 4 years the scanner will be replaced.



2.  Let x represents Michael age in years now.
     
                            
                          Now           4years later  
                            
Michael                 x                 x + 4

      
John                      x - 17           (x - 17) + 4


                              x + 4 + x - 17 + 4 = 49
                               x + 4 + x - 13 = 49
                                2x - 9 = 49
                                 2x - 9 + 9 = 49 + 9
                                            2x = 58
                                     (1/2)(2x) = (1/2)(58)
                                                x = 29, Michaels age is 29


3. Brady speed 1   Rate(mph)       Time(hours)           Distance(miles)
                                17                     t                               17 t
     Brady speed 2    22                     4 - t                         22(4 - t)total distance

The total distance he rode  17t + 22(4 - t) = 70

The total distance = 70 miles


                                         showing work:  
                                           17t + 22(4 - t) = 70
                                            17t + 88 - 22t = 70
                                             - 5t + 88 = 70
                                              - 5t + 88 - 88 = 70 - 88
                                               - 5t  = - 18
                                                t = 3.6, Brady rode 17(mph) for 3.6(hrs).


4. t = the price of 1 shirt
     4t - 39.58 = 52.22
     4t - 39.58 = 52.22 + 39.58
      4t  + 0 = 91.80
    (1/4)(4t) = (1/4)(91.80)
               t = 22.95, price of 1 shirt was $22.95


5. Let M represent number of months.
      3.5m + 90 = 132
       3.5m + 90 - 90 = 132 - 90
        3.5m = 42
    (1/3.5)(3.5m) = (1/3.5)(42)
                      m = 12, the boy will grow 132cm tall, 12 months from now



6.   Let N represent given number
         n + 1/6n + (2 1/2)n + 7 = 12 1/2
          n ( 1 + 1/6 + 5/2) + 7  = 12 1/2
          n(6/6 + 1/6 + 15/6) + 7 = 12 1/2
           n(22/6 + 7 - 7 = 12 1/2
            11/3n + 7 - 7 = 12 1/2 - 7
              11/3n + 0 = 5 1/2
              11/3n = 5 1/2
               3/11.11/3 = 3/11.11/2
                 1n  = 3/2
                    n = 1 1/2, is the number


7. let X represents the first number, then 33 - x represents the other # since their sum is 33
     X - (33 - x) = 2
      X + ( - (33 - x)) = 2
      X + ( -33) + X = 2
       2x + (- 33) = 2
        2x + (- 33) + 33 = 2 + 33
        2x + 0 = 35
        1/2 * 2x = 1/2 * 35
         1x = 35/2
          x = 17 1/2

33 - x = 33 - (17 1/2) = 15 1/2
                     {17 1/2,  15 1/2}
                                 



8. Let T represents number of tokens in machine A. Then 1/2T represents the number of tokens in machine B, and 3/4T represents the number of tokens in machine C.

   T + 1/2T + 3/4T = 18,324
    9/4T = 18, 324
          T = 8, 144
Machine A took 8,144T, Machine B 4,072T, Machine C 6,108T



9.  Let Z represents the cost of a pencil in dollars. Then, the cost of a pen in dollars is Z + 0.11

   250(Z + Z + 0.11) = 42.5
    250(2Z + 0.11) = 42.5
    500Z + 27.5 = 42.5
    500Z + 27.5 + ( - 27.5) = 42.5 + ( -27.5)
     500Z + 0 = 15
     500Z = 15
      500Z/500 + 15/500
             Z = $0.03, a pencil costs, and  a pens cost $0.14


10. Let R represents speed in mph of faster car, Then r - 7 represents speed in mph of slow car.

 5 1/2(r) + 5 1/2(r - 7) = 599.5
  5 1/2(r + r - 7) = 599.5
 5 1/2(2r - 7) = 599.5
 11/2 (2r - 7) = 599.5
  2/11 * 11/2 (2r - 7) = 2/11 * 599.5
  1 * (2r - 7) = 1199/11
   2r - 7 = 109
   2r  - 7 + 7 = 109 + 7
   2r + 0 = 116
   2r = 116
 1/2 * 2r = 1/2 * 116
          1r = 58
             r =58

Faster car average speed is 58mph
Slower car average speed is 51mph

Distance = rate * time
 d = 51 * 5 1/2
  d = 51 * 11/2
   d = 280.5


Slower car travel 280.5 miles in 5 1/2hrs
d = 58 * 5 1/2
d = 58 * 11/2
d = 319           or  599.5 - 280.5 = 319


Faster car travel 319 miles in 5 1/2 hrs




The slower car travels 280.5 miles in 5 1/2hrs. remainder of trips for both vehicle is 38.5 miles, because, 319 - 280.5 = 38.5


distance = rate * time
38.5 = 51 (t)
1/51(38.5) = 1/51(51)(t)
38.5/51 = 1t
77/102 = t, This time is in hours. To convert to minutes, multiply by 60 minutes per hour
77/102 * 60 = 77/51 * 30 = 2310/51 = 45, The slower car will arrive at about 45 minutes after the first car.



Hope this helps!!!


Next time please ask for help in chunks!! Try for yourself.. this is a lot...








5 0
3 years ago
Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of
Misha Larkins [42]

This question is incomplete, the complete question is;

Assume that body masses of Goldfinch birds follow a normal distribution, with a standard deviation equal to 0.04 oz. An ornithologist who would like to make some inference about the average body mass of the Goldfinch birds. In particular, at a significance level of 0.01, she would like to test the null hypothesis H₀: Average body mass of the Goldfinch birds is 0.5 oz, against the alternative claim that average body size is less than 0.5 oz.

      Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of the sample mean, that will allow the experimenter reject the null and prove the alternative at significance level 0.01. For this problem, make sure that your solution includes all steps of your computation. You will not earn points if you just use a formula

Answer: the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

Step-by-step explanation:

Let us consider testing a hypothesis about a population mean with population standard deviation that is known,

Let the average body mass of the Goldfinch bird be μ^μ

Now our hypotheses are will be;

H₀ : μ = 0.5    and

H₁ : μ < 0.5

For the test, we shall use the z statistic which will be

z = (x"-μ)/(σ/√n)

Now given that;

σ = 0.04 and n = 4  

sample mean x" = ?

Now in order to be able to reject the null hypothesis, the p-value should be ≤ α = 0.01.

so to find the largest value of sample mean, we will use the maximum of p-value that is 0.01.

For a p-value = 0.01 at the lower tail (which is the percentile for z),

the corresponding z will be -2.33

so we substitute our values into our formula

z = (x"-μ)/(σ/√n)

z(σ/√n) = (x"-μ)

-2.33(0.04/√n) = (x"-0.5)

-0.0466 = x" - 0.5

x" = 0.5 - 0.0466

x"= 0.4534

therefore the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

4 0
3 years ago
Help me please chile
jekas [21]

Answer:

1 neither

2 supplementary

3 supplementary

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
How to solve this triangle ABC?<br>i did super wrong all :( who can help me please?
Alex73 [517]

It looks like you had some of the numbers correct, but you just labeled it and rounded it incorrectly, and the teacher gave you super partial credit for it.  

For my work, I'm assuming that side A is opposite of angle A and side B is opposite of angle B, etc...



5 0
3 years ago
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