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evablogger [386]
2 years ago
7

consider the equations y=3x+7 and 5x+2y=3. Solve the system equations by graphing. Give your solution to the system as a pair of

cooridanites
Mathematics
1 answer:
alexandr402 [8]2 years ago
7 0

Answer:

(1,4)

Step-by-step explanation:

The two lines intersect at 1,4 when you graph them

The first equation is already in slope intercept from, so you know the y-int. is 7 and the slope is 3. However, the second equation must be put in slope int. form.

5x+2y=3

move the y to the other side

5x=3-2y

move the 3 to the other side, so the y variable is by itself

5x-3=-2y

divide by -2 to the equation is equal to y

(-5x/2)+(3/2)=y

you now know the y int. of the second equation is 3/2 and the slope is -5/2

know that you know the slop int. formulas for both equations you can graph them

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Find the length of the missing side. Give your answer in the simplest radical form.
taurus [48]

Answer:

x = 2\sqrt{5}

Step-by-step explanation:

Use Pythagorean theorem,

Hypotenuse² = base² + altitude²

x² = (√8)² + 4²

  =  8 + 16

  = 20

x = √20 = \sqrt{2*2*5} = 2\sqrt{5}

x = 2\sqrt{5}

6 0
3 years ago
Simplify. Re-write in radical form last, simplify any roots if possible. <br><br> (x^6)^1/8
GREYUIT [131]
I hope this helps you


x^6.1/8


x^3/4


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3 0
3 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
Rewrite the equation y – 4x = –9 in slope-intercept form.
Vera_Pavlovna [14]
The answer to your question is A. Y= -4x-9 because is you look at the pre written equation it shows that 4x is negative and that 9 is negative too. Also, if you rewrite an equation you have to isolate Y. Therefore A is the correct answer
3 0
3 years ago
Read 2 more answers
Interior and Exterior Triangle Angles
Luden [163]

Sum of two interiors=exterior

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6 0
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