A volume of a pyramid=base area×height/3
both the bases have same dimensions
pyramid B is twice the height of A
therefore the volume is doubled
The formula of nth term is = 10 - 3n
What is AP?
- A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms. Take the numbers 5, 7, 9, 11, 13, and 15 as an example. . . is a sequence of numbers having a common difference of two.
- The n-th term of the sequence is given by:, if the beginning term of an arithmetic progression is and the common difference between succeeding members is, then
- If the AP contains m phrases, then denotes the final term, which is given by:
- The term "finite arithmetic progression" or "arithmetic progression" refers to a finite segment of an arithmetic progression. An arithmetic series is the total of a finite arithmetic progression.
Acc to our question-
- For the nth term in an algebraic series
- U(n) = a + (n - 1)d
- the number of terms is n.
- The first term is a.
- d is the typical difference
- From the preceding sequence
- a = 7
- d = 4 - 7 = - 3
- The nth term's formula is
- U(n) = 7 + (n - 1)-3
- = 7 - 3n + 3
- The ultimate solution is
- = 10 - 3n
Hence,The formula of nth term is = 10 - 3n
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Answer:
i
Step-by-step explanation:
Answer:
A P of Addition
Step-by-step explanation:
Answer:
(2)(120)(80) + (2)(120)(50) - (4)(60)(5²)
Step-by-step explanation:
The lateral faces of the building are the 4 sides of the building consisting:
2 rectangles of 120 ft by 80 ft
Area of the two rectangular faces = (2)(120)(80)
And
2 rectangles of 120 ft by 50 ft
Area of the two rectangular faces = (2)(120)(50)
✔️Total lateral surface area of the building = (2)(120)(80) + (2)(120)(50)
Note: we are asked to find the expression that represents the total surface area that needs to be painted given that there are 60 windows on each lateral face of the building of the shape of a square with side lengths of 5 ft.
Therefore, the total lateral surface area of the building that will be painted = total lateral surface of the building - total area covered by the 60 windows on each face of the building
Surface area covered by 60 windows in the 4 lateral face of the building = (4)(60)(5²)
✅total lateral surface area of the building that will be painted = (2)(120)(80) + (2)(120)(50) - (4)(60)(5²)
