The quantities in the proportion you give add to 16 pounds, of which 2 pounds are cement. That is, cement constitutes 1/8 of the total weight.
For each yard of concrete, 4000 lb/8 = 500 lb of cement are used.
For 12.5 yards of concrete, 12.5 * 500 = 6,250 pounds of cement will be used.
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"yard" in this case is shorthand for "cubic yard".
You do not need to use the remainder theorem to find p(3). Just plugin 3 where the x is located in


Answer is a.
Sin0= y/r
X= -4 and r= 9 (radius is also the hypotenuse)
In quadrant II y is positive
X^2 +y^2 = r^2
-4^2 + y^2 = 9^2
16 + y^2 = 81
Y^2 = 81-16
Y^2 = 65
Y= sqrt65
Sin0= sqrt65/9
Use the slope formula.
Subtract the y-coordinates.
Subtract the x-coordinates in the same order.
Divide the difference in y by the difference in x.
slope = m = (y2 - y1)/(x2 - x1)
slope = (5 - 7)/(-2 - (-1)) = -2/(-1) = 2
slope = 2