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kotegsom [21]
3 years ago
5

The pizza shown has a radius of 11 cm. What is the approximate area of the pizza? (Use 3.14 for .)

Mathematics
2 answers:
Artist 52 [7]3 years ago
6 0
The approximate area of the pizza is 13cm
irga5000 [103]3 years ago
4 0
A=\pi  r^{2}
A= 3.14*11^{2}
A=3.14*121
A=379.94 cm^{2}
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Find the area of the segment (unshaded area) of Circle G with radius 4in. Round to the nearest tenth.
Romashka [77]

Angle is 90°

The sector is 1/4 th of circle

Area of sector

  • πr²/4
  • π(4)²/4
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Triangle is right angled

Area

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  • 16/2
  • 8in²

Area of unshaded region

  • 4π-8
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1 year ago
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Show how to rewrite 1/5 with the denominator 10.
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Answer:

first blank: 2

second blank: 2

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2 years ago
Keith plans to buy a car in the future. He currently has $3,000 saved up to buy the car. How much money (x) does he need to save
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708.33333333 or 708.4 $ a month
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3 years ago
An experiment involves 30 participants. From these, a group of 4 participants is to be tested under a special condition. How man
zheka24 [161]

Answer:

7

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2 years ago
Determine which of these sequences is an arithmetic sequence. Then determine the explicit formula that would be used to define t
vagabundo [1.1K]

6)

34, 43, 52, 61, ...

43-34 = 9; 52-43 = 9; 61-52 = 9

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 34

difference:  d = 9

so the formula:

                         a_n=a+d(n-1)\\\\a_n=34+9(n-1)\\\\a_n = 34+9n-9\\\\\underline{a_n=9n+25}

7)

10, 6, 2, -2, ...

6-10 = -4; 2-6 = -4; -2-2 = -4

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 10

difference:  d = -4

so the formula:

                         a_n=a+d(n-1)\\\\a_n=10+(-4)(n-1)\\\\a_n = 10-4n+4\\\\\underline{a_n=-4n+14}

8)

-3, -10, -17, -24, ...

-10-(-3) = -7; -17-(-10) = -7; -24-(-17) = -7

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = -3

difference:  d = -7

so the formula:

                         a_n=a+d(n-1)\\\\a_n=-3+(-7)(n-1)\\\\a_n =-3-4n+7\\\\\underline{a_n=-7n+4}

9)

7, 8.5, 10, 11.5, ...

8.5-7 = 1.5; 10-8.5 = 1.5; 11.5-10 = 1.5

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 7

difference:  d = 1.5

so the formula:

                         a_n=a+d(n-1)\\\\a_n=7+1.5(n-1)\\\\a_n =7+1.5n-1.5\\\\\underline{a_n=1.5n+5.5}

10)

30, 22¹/₂, 15, 7¹/₂, ...

22¹/₂-30 = -7¹/₂;   15-22¹/₂ = -7¹/₂;   7¹/₂-15 = -7¹/₂

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 30

difference:  d = -7¹/₂

so the formula:

                         a_n=a+d(n-1)\\\\a_n=30+(-7\frac12)(n-1)\\\\a_n =30-7\frac12n+7\frac12\\\\ \underline{a_n=-7\frac12n+37\frac12}

6 0
2 years ago
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