Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
A normal space<span> is a </span>topological space X<span> that satisfies </span><span>Axiom T4</span><span>: every two disjoint </span>closed sets<span> of </span>X<span> have disjoint </span>open neighborhoods<span>.</span>
Answer:
Step-by-step explanation:
The given sequence is
-12,-16,-20...
The first term of this sequence is 
.
The common difference is
The nth term of this arithmetic sequence is;
We substitute the values for the first term and the common difference to obtain;
Answer:
It is a rational number
Step-by-step explanation:
It is a rational number because -6/7 is equal to -0.857142 repeating. And a rational number repeats.
Hope this helps☝️☝☝
Answer:
Hi san, A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, given an element x in X, there is only one element in Y that x is related to. For example, consider the following sets X and Y.
This should help you a bit.
